SpringMVC servlet映射 [英] SpringMVC servlet mapping
问题描述
我写了一个非常简单的Spring MVC应用程序。我很抱歉我对Spring MVC很新，所以请耐心等待。
I've written a really simple Spring MVC app. I apologise I'm rather new to Spring MVC so bear with me.
web.xml如下：
The web.xml is as follows
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
我的第一个问题是，我有一个用于登录的jsp页面，代码如下......
My first question is, I have a jsp page for login with the following code...
<form action="/login" method="post" >
Username : <input name="username" type="text" />
Password : <input name="password" type="password" />
<input type="submit" />
</form>
这给出了404但是在我的控制器中，我已经将控制器映射到/ login和代码下面...
This gives a 404 but in my Controller, I've mapped the controller to /login with the code below...
@Controller
public class LoginController {
private static final Logger logger = LoggerFactory.getLogger(LoginController.class);
/**
* Simply selects the home view to render by returning its name.
*/
@RequestMapping(value = "/login", method = RequestMethod.POST)
public String home(Locale locale, Model model, String username, String password) {
if(username.equalsIgnoreCase("david"))
{
logger.info("Welcome home! the client locale is "+ locale.toString());
Date date = new Date();
DateFormat dateFormat = DateFormat.getDateTimeInstance(DateFormat.LONG, DateFormat.LONG, locale);
String formattedDate = dateFormat.format(date);
model.addAttribute("serverTime", formattedDate );
return "home";
}
else
{
return "void";
}
}
}
<我的理解是@requestmapping应该执行servlet映射而不是web.xml，这是正确的吗？如果需要，还会在下面显示/WEB-INF/spring/appServlet/servlet-context.xml的值。
My understanding is the @requestmapping should do the servlet mapping rather than in the web.xml, is this correct? The value of /WEB-INF/spring/appServlet/servlet-context.xml is shown below also if needed.
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->
<!-- Enables the Spring MVC @Controller programming model -->
<annotation-driven />
<!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
<resources mapping="/resources/**" location="/resources/" />
<!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory -->
<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
</beans:bean>
<context:component-scan base-package="org.david.myapp" />
</beans:beans>
所以我的第一个问题是：是在web.xml或@requestmapping中完成的servlet映射在控制器类？
So my first question is : is the servlet mapping done in the web.xml or at the @requestmapping in the controller class?
第二个问题：如果要继续使用webxml，建立此页面以获得更多页面的最佳方法是什么？我应该为每个网址创建一个控制器吗？我应该为每个网址创建一个servlet上下文吗？
Second question : what's the best way to architect this to have more pages, should I keep appending to the webxml? Should I create a controller for every url? Should I create a servlet-context for every url?
感谢您阅读：）
推荐答案
您已将< url-pattern> 定义为 / ，这意味着您的 appServlet 只会收到对根网址的请求。通过将其更改为 / * ， appServlet 将获取所有传入请求。这可行，但你也可以考虑创建一个特定的 loginServlet ，它可以映射到url / login / * 。
You have defined <url-pattern> to be /, which means that your appServlet will only receive requests to the root url. By changing it to /* the appServlet will get all incoming requests. This will work, but you can also consider to create a specific loginServlet which could be mapped to url /login/*.
- 您可以在一个
web.xml中定义多个servlet。通过添加更多< servlet-mapping>标记来指定每个servlet的命令。 - servlet可能有许多控制器。通常，一个控制器服务于您域的特定部分，例如
PersonController，AddressController等。 - 每个控制器通常会处理几个网址在逻辑上组合在一起，例如
/ persons / {id}，/ persons / search，/ persons / add等。
- You can have multiple servlets defined in a single
web.xml. Which request will hit each servlet is specified by adding more<servlet-mapping>tags. - A servlet may have many controllers. Typically, one controller serves a specific part of your domain, e.g.
PersonController,AddressController, etc. - Each controller usually handles several urls that are logically grouped together, e.g.
/persons/{id},/persons/search,/persons/add, etc.
这篇关于SpringMVC servlet映射的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
