在Java中使用AudioPlayer [英] Working with AudioPlayer in Java

问题描述

在我的swing应用程序中，我使用一个类来点击鼠标时发出声音。我遇到的问题是，当我打电话给班级时，声音会被播放一次，当突然看到另一个按钮时，它就不会播放声音。我尝试延迟我的代码，但仍然无法正常工作。它与线程有关吗？我不擅长线程所以请告诉我如何做到这一点。我使用的代码如下，

In my swing application i am using a class to play a sound when the mouse is clicked. The problem i have is when i call the class the sound is played onetime and when suddenly another button is clicked it doesn't play the sound. I tried giving a delay in my code but stilll id doesn't work as i expected. Is it something to do with threads ?? I am not good at threads so please tell me how to do that. The code i am using is as below,

package utilities;  
import java.applet.AudioClip;  
import java.io.File;  
import java.io.IOException;  
import java.io.InputStream;   
import java.net.URL;  
import java.util.logging.Level;  
import java.util.logging.Logger;  
import sun.audio.AudioData;  
import sun.audio.AudioPlayer;  
import sun.audio.AudioStream;  
import sun.audio.ContinuousAudioDataStream;  
public class Tone {`  

    File wavFile = new File("sounds/Windows Default.wav");
    URL urlClick = Tone.class.getResource("/sounds/WindowsDefault.wav");
    AudioClip sound;
    public void sound() {
        AudioStream as = null;
        try {

            InputStream in = this.getClass().getResourceAsStream("/sounds/WindowsDefault.wav");
            as = new AudioStream(in);
            AudioData data = as.getData();
// Create ContinuousAudioDataStream.
ContinuousAudioDataStream cas = new ContinuousAudioDataStream (data);
            //System.out.println(as.getLength());
            AudioPlayer.player.start(cas);

            //System.out.println(urlClick);
                //sound = Applet.newAudioClip(urlClick);
        //this.wait(1000);
           for(int i =0;i<100000;i++){
               double k = Math.pow(i, 5);
               if(i==99999){
                   AudioPlayer.player.stop(cas);
                   return;
               }
           }
           // sound.play();
            String relativeDirectory = System.getProperty("user.dir");
            System.out.println(relativeDirectory);

        } catch (IOException ex) {
            Logger.getLogger(Tone.class.getName()).log(Level.SEVERE, null, ex);
        } finally {
            try {
                as.close();
            } catch (IOException ex) {
                Logger.getLogger(Tone.class.getName()).log(Level.SEVERE, null, ex);
            }

        }

    }

    public static void main(String[] args) {
Tone tone = new Tone();
tone.sound();
System.out.println("done");

    }
}

- 编辑 -
我使用continuousaudiostream的原因是因为当我使用此aleast听到一些声音时声音根本没有发生。即使我使用AudioStream问题就在那里..

--EDIT-- The reason why i used the continuousaudiostream is because the sound was not happening at all when i use this aleast hear some sound. Even when i used AudioStream the problem was there..

推荐答案

1）最好不要使用隐藏的类/ api - 因为你已经有了阅读你在其他问题中得到的链接： - ）

1) Better not use hidden classes/api - as you already have read in the link you got in your other question :-)

2）在开始/重新打开之前停止/关闭已经运行的声音，在公共场合像：

2) stop/close an already running sound before starting/re-open again, in public api something like:

Clip clip;

private void doPlay(final String url) {
    try {
        stopPlay();
        AudioInputStream inputStream = AudioSystem
                .getAudioInputStream(getClass().getResourceAsStream(url));
        clip = AudioSystem.getClip();
        clip.open(inputStream);
        clip.start();
    } catch (Exception e) {
        stopPlay();
        System.err.println(e.getMessage());
    }
}

private void stopPlay() {
    if (clip != null) {
        clip.stop();
        clip.close();
        clip = null;
    }
}

（注意：完全关闭仅供参考，请完善加载一次然后再次停止/启动的逻辑）

(Note: completely closed for illustration only, refine the logic to load once and then stop/start again)

这篇关于在Java中使用AudioPlayer的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！