从Java中的列表中选择多个随机元素 [英] Pick multiple random elements from a list in Java

问题描述

所以说我有

List<String> teamList = new LinkedList<String>()
teamList.add("team1");
teamList.add("team2");
teamList.add("team3");
teamList.add("team4");
teamList.add("team5");
teamList.add("team6");

是否有一种简单的拣货方式......说明这个清单中的6个元素中的3个随机方式没有选择相同的元素两次（或更多次）？

Is there a simple way of picking... say 3 out the 6 elements in this list in a randomized way without picking the same element twice (or more times)?

推荐答案

试试这个：

public static List<String> pickNRandom(List<String> lst, int n) {
    List<String> copy = new LinkedList<String>(lst);
    Collections.shuffle(copy);
    return copy.subList(0, n);
}

我假设输入列表中没有重复的元素，我采取预防措施改组副本，使原始列表不受干扰。它的调用方式如下：

I'm assuming that there are no repeated elements in the input list, also I take the precaution of shuffling a copy for leaving the original list undisturbed. It's called like this:

List<String> randomPicks = pickNRandom(teamList, 3);

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