setter的Lambda表达式 [英] Lambda expression for setter
本文介绍了setter的Lambda表达式的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我们可以为getter使用lambda表达式,如下所示
We can lambda expression for getter as below
Function<Student, String> studentNameGetter = Student::getName;
如何为setter创建lambda表达式?
How about creating lambda expression for the setter?
推荐答案
我不确定你为setter创建一个lambda表达式是什么意思。
I'm not sure what you mean by creating a lambda expression for the setter.
您尝试做的是将方法引用分配给合适的功能接口。在这种情况下,最佳匹配是 BiConsumer
:
What it looks like you are trying to do is to assign the method reference to a suitable Functional Interface. In that case, the best match is to a BiConsumer
:
BiConsumer<Student, String> studentNameSetter = Student::setName;
这篇关于setter的Lambda表达式的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文