使用/不使用nanoOfSeconds将字符串转换为LocalTime [英] Coverting String to LocalTime with/without nanoOfSeconds

问题描述

我需要将一个字符串转换为LocalTime（java-8而不是joda），该字符串可能有也可能没有nanoOfSeconds。 String格式的形式为
07:06:05 或 07：06：05.123456
字符串在秒内可能有或没有小数位，当它出现时，可以有任意数量的字符来表示Nano Seconds部分。

I need to convert a string to LocalTime (java-8 not joda) that may or maynot have nanoOfSeconds in the string. The String format is in the form of 07:06:05 or 07:06:05.123456 The string may or may not have a decimal place in the seconds and when it does there could be any number of characters to represent the Nano Seconds part.

使用DateTimeForamtter，例如

Using a DateTimeForamtter such as

DateTimeFormatter dtf = DateTimeFormatter.ofPattern("H:mm:ss");

或

DateTimeFormatter dtf = DateTimeFormatter.ofPattern("H:mm:ss.SSSSSS");

我可以使用IF语句来区分两种格式，例如：

I can use an IF statement to distinguish between the two formats such as:

DateTimeFormatter dtf;
if (time1.contains(".") {
   dtf = DateTimeFormatter.ofPattern("H:mm:ss.SSSSSS);
} else {
   dtf = DateTimeFormatter.ofPattern("H:mm:ss);
}

这很好，我' m好吧，但我需要能够在小数点后使用不同数量的位置。

This works fine and I'm OK with this but I need to be able to also use a varying number of positions after the decimal point.

示例数据集可能是：

[11:07:59.68750, 11:08:00.781250, 11:08:00.773437500, 11:08:01]

有没有办法允许格式化程序解析小数点后的任意位数而不抛出 java.time.format.DateTimeParseException 当小数位数未知时？

Is there a way to allow the formatter to parse any number of digits after the decimal without it throwing a java.time.format.DateTimeParseException when the number of decimal places is unknown?

我希望我遗漏一些非常简单的东西。

I'm hoping I missing something really simple.

推荐答案

没有必要做任何特殊的事情来解析这种格式。 LocalTime.parse（String）已处理可选的纳秒：

There is no need to do anything special to parse this format. LocalTime.parse(String) already handles optional nanoseconds:

System.out.println(LocalTime.parse("10:15:30"));
System.out.println(LocalTime.parse("10:15:30."));
System.out.println(LocalTime.parse("10:15:30.1"));
System.out.println(LocalTime.parse("10:15:30.12"));
System.out.println(LocalTime.parse("10:15:30.123456789"));

以上所有解析都很好，另见 Javadoc spec 。

All the above parse fine, see also the Javadoc spec.

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