声纳严重违规 - 以前取消引用的Nullcheck值 [英] Sonar critical violation - Nullcheck of value previously dereferenced
问题描述
对于我在我的一个测试类中的下面一段代码,Sonar抛出了一个严重的违规行为 - 正确性 - 以前取消引用的价值的Nullcheck
For the below piece of code I have in one of my test classes, Sonar throws me a critical violation - Correctness - Nullcheck of value previously dereferenced
if (testLst != null && !testLst.isEmpty()) {
for (Test test : testLst) {
if (test.getName().equalsIgnoreCase("TEST")) {
// do blah
}
有人可以关于我在这里做错了什么呢?
Can someone throw some light on this on what am I doing wrong here?
编辑:这里的答案之一建议这是因为我之前可以访问变量,所以空检查是多余的。但事实并非如此。这是我的空检查之前的代码行。
One of the answers here suggested this is because I could have accessed the variable before, and so the null check is redundant. That's not true though. Here is the line of code before my null check.
testLst = myTest.getValues(); //I am basically populating the array by doing a get, but I am not accessing the list itself by doing a get on it directly - like testLst.get()
if (testLst != null && !testLst.isEmpty()) {
for (Test test : testLst) {
if (test.getName().equalsIgnoreCase("TEST")) {
// do blah
}
推荐答案
当您检查时会显示此消息如果变量的值为null(在本例中为 testLst
),则之前已经访问过该变量。不需要空检查,因为如果值为null,则抛出 NullPointerException
。
This message is shown when you're checking if a variable's value is null (in this case testLst
) whereas you already accessed the variable before. The null check is not needed since if the value was null, a NullPointerException
would have been thrown.
示例:
testLst.remove(something);
if (testLst != null && !testLst.isEmpty()) {
for (Test test : testLst) {
if (test.getName().equalsIgnoreCase("TEST")) {
// do blah
}
支票 testLst!= null
是多余的,因为当程序到达 if
语句时, testLst
不能为null,否则前面的语句 testLst.remove(某事物)
会抛出 NullPointerException
。在这种情况下,您应该在访问 testLst
之前,在 为空的地方放置空检查:
The check testLst != null
is redundant since at the time the program reaches the if
statement, testLst
cannot be null, otherwise the previous statement testLst.remove(something)
would have thrown a NullPointerException
. In this case, you should place the null check before accessing testLst
, in a place where it can be null:
if(testLst != null) {
testLst.remove(something);
if (!testLst.isEmpty()) {
for (Test test : testLst) {
if (test.getName().equalsIgnoreCase("TEST")) {
// do blah
}
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