请求被拒绝，因为没有找到多部分边界 [英] The request was rejected because no multipart boundary was found
问题描述
我在LightBox中使用一个Form，其中包含一些输入元素。
I am using a Form in a LightBox which contains some input element.
<form name="imageUploadForm" action="uploadImage.do" method="post" enctype="multipart/form-data">
<input type="text" id="id" name="id" style="display: none;" value="">
<div id="fileUploaderDiv">
<input type='file' name="file0" id ="file0" />
</div>
<input type="submit" value="Submit">
</form>
当我提交表单时，表格重定向到其行动地点。我只想在不重定向用户的情况下提交表单，这样用户就可以在灯箱上停留而不会丢失他的数据。
when i am submitting the form than the form redirect to it's action location. I just want to submit form without redirecting user, so user stay on lightbox without loosing his data.
我已经尝试了jquery ajax调用此
I have tried jquery ajax call for this
var data = new FormData();
var $inputs = $('#imageUploadForm :input');
var values = {};
$inputs.each(function() {
values[this.name] = $(this).val();
data.append(this.name, $(this).val());
});
$.ajax({
url: 'uploadImage.do',
data: data,
cache: false,
contentType: 'multipart/form-data',
processData: false,
type: 'POST',
success: function(data){
alert(data);
}
});
但是在我的FileUploader servlet中服务器端出错。
But getting error at server side in my FileUploader servlet.
The request was rejected because no multipart boundary was found
任何人都可以告诉我这里缺少什么？
can anybody tell me what am i missing in this ?
推荐答案
这是使用jquery提交表单的最简单形式阿贾克斯。我没有测试过，但它应该可以工作： - ）
Here is the simplest form of a form submit using jquery Ajax. I have not tested this but it should work :-)
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Test form</title>
<script src="http://code.jquery.com/jquery-latest.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('#sbmt').click(function(){
var text1 = $('#text1').val();
var text2 = $('#text2').val();
/// validation of inputs
///then
$.ajax(
{
url :'submit.php',
type : 'post',
data : {'text1' : text1, 'text2' : text2 },
success: function(data){
alert("form submitted . response is :"+ data);
}
}
).fail(function(){alert("Failed!!");});
});
});
</script>
</head>
<body>
<form id="myform">
<input type="text" id="text1" />
<input type="text" id="text2" />
<input type="button" id="sbmt" value="submit"/>
</form>
</body>
</html>
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