基于Java的正则表达式，允许使用字母数字字符和'，和 [英] Java-based regular expression to allow alphanumeric chars and ', and

问题描述

我是Java中正则表达式的新手，我需要验证字符串是否只包含字母数字字符，逗号，撇号和句号（句点）。其他任何东西都应该等于假。

I'm new to regular expressions in Java and I need to validate if a string has alphanumeric chars, commas, apostrophes and full stops (periods) only. Anything else should equate to false.

任何人都可以提供任何指示吗？

Can anyone give any pointers?

我现在有这个我相信字符串中每个字符都有字母数字：

I have this at the moment which I believe does alphanumerics for each char in the string:

 Pattern p = Pattern.compile("^[a-zA-Z0-9_\\s]{1," + s.length() + "}");

谢谢

Albany Caxton先生

Mr Albany Caxton

推荐答案

我是Java中正则表达式的新手，我需要验证字符串是否正确只有字母数字字符，逗号，撇号和句号（句点）。

I'm new to regular expressions in Java and I need to validate if a string has alphanumeric chars, commas, apostrophes and full stops (periods) only.

我建议您使用 \p {Alnum} 类来匹配字母数字字符：

I suggest you use the \p{Alnum} class to match alpha-numeric characters:

Pattern p = Pattern.compile("[\\p{Alnum},.']*");

（我注意到你包括 \s 在当前模式中。如果您也想允许空格，只需在字符类中添加 \s 。）

(I noticed that you included \s in your current pattern. If you want to allow white-space too, just add \s in the character class.)

来自 <$ c的文档$ c>模式 ：

[...]

[...]

\p {Alnum} 一个字母数字字符： [\p {Alpha} \p {Digit} ]

\p{Alnum} An alphanumeric character:[\p{Alpha}\p{Digit}]

[...]

---

您不需要包含 ^ 和 {1，...} 。只需使用 Matcher.matches 或 String.matches 等方法来匹配完整模式。

---

You don't need to include ^ and {1, ...}. Just use methods like Matcher.matches or String.matches to match the full pattern.

另外，请注意，您不需要在字符类中转义。（ [ ... ] ）。

Also, note that you don't need to escape . within a character class ([...]).

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