生成号码列表在C＃ [英] Generating numbers list in C#

问题描述

我经常需要生成号码清单。该时间间隔可以有相当多的数字。我有这样一个方法：

I often need to generate lists of numbers. The intervals can have quite a lot of numbers. I have a method like this:

public static int[] GetNumbers(int start, int end)
{
    List<int> list = new List<int>();
    for (int i = start; i < end; i++)
        list.Add(i);
    return list.ToArray();
}

有没有一种方法，使之更简单，更快捷？

Is there a way to make it simpler, faster?

我使用.NET 3.5

I am using .NET 3.5

推荐答案

这可能会是一个快一点 - 它肯定更简单：

This would probably be a bit faster - and it's certainly simpler:

int[] values = Enumerable.Range(start, end - start).ToArray();

你绝对需要它作为一个数组有关系吗？如果你只需要遍历它，你可以只使用<一href="http://msdn.microsoft.com/en-us/library/system.linq.enumerable.range.aspx"><$c$c>Enumerable.Range直接获得一个的IEnumerable＆LT; INT＆GT; 这从来不需要实际持有内存中的所有号码在同一时间

Do you definitely need it as an array though? If you only need to iterate over it, you could just use Enumerable.Range directly, to get an IEnumerable<int> which never needs to actually hold all the numbers in memory at the same time.

这篇关于生成号码列表在C＃的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！