Array-List里面的构造函数作为参数之一，如何创建一个新对象？ [英] Array-List inside constructor as one of the parameter, how to create a new object?

问题描述

我遇到一个构造函数的问题，该构造函数将arrayList作为参数之一。

i am having problem with a constructor that takes an arrayList as one of the arguments.

public class ItemisedProductLine extends ProductLine{

public static ArrayList<String> serialNumbers;

public ItemisedProductLine(String productCode, double recRetPrice, double salePrice, int quantity, String description, ArrayList<String> SerialNumbers){
    super( productCode,  recRetPrice,  salePrice,  quantity,  description);
    this.serialNumbers = serialNumbers;
}    

}

现在在我的班级库我想实例化一个新的ItemisedProductLine并将序列号的arryList传递给构造函数

Now in my class Inventory i want to instantiate a new ItemisedProductLine and pass an arryList of serial number to the constructor

ItemisedProductLine item = new ItemisedProductLine("productCode", 2600, 2490, 2, "descrpition", new ArrayList<String>("1233456", "6789123"));

这在Java中是否可行？它似乎不是一个常见的任务，没有找到任何例子。

Is this possible in Java? It seem to be not a common task to do, did not found any example.

作为替代，我可以使用通用数组而不是Array-List但是我可以因为未知的大小而没有初始化

As alternative i could have used an generic array instead of Array-List but then i can not initialize it because of the unknown size

我希望我不会忘记另一个括号： - ）

Let's hope i'm not forgetting another parenthesis :-)

最后一件事是错误是找不到合适的构造函数ArraList<>

Last Thing is the error is "no suitable constructor found ArraList<>"

推荐答案

你可以尝试：

new ArrayList<String>(Arrays.asList("1233456", "6789123"))

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