将XML文件转换为具有List的XML对象 [英] Convert XML file into an XML object having a List

问题描述

可能重复：

适用于Java的最佳XML解析器

如何将这个xml文件转换为XML对象？

我有这样的XML。我想将其转换为JAVA对象。

I have a XML like this . And i want to convert it into JAVA object.

<P1>
    <CTS>
        Hello
    </CTS>
    <CTS>
        World
    </CTS>
<P1>    

所以我创建了以下带有属性的java类。

So I created following java classes with their properties.

P1类

@XmlRootElement
public class P1 {
    @XmlElement(name = "CTS")
    List<CTS> cts;
}

CTS class

public class CTS {
    String ct;
}

测试类

File file = new File("D:\\ContentTemp.xml");
            JAXBContext jaxbContext = JAXBContext.newInstance(P1.class);

            Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
            P1 p = (P1) jaxbUnmarshaller.unmarshal(file);

但我收到以下错误 -

But I am getting following error -

com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException: 
2 counts of IllegalAnnotationExceptions
Class has two properties of the same name "cts"

推荐答案

更新

com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException：2
IllegalAnnotationExceptions类的数量有两个属性
同名cts

com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException: 2 counts of IllegalAnnotationExceptions Class has two properties of the same name "cts"

默认情况下a JAXB（JSR-222） 实现基于属性创建映射和注释的字段。当您注释一个也有属性的字段时，它将导致此错误。

By default a JAXB (JSR-222) implementation creates mappings based on properties and annotated fields. When you annotate a field for which there is also a property it will cause this error.

选项＃1 - 使用@XmlAccessorType（XmlAccessType.FIELD）

您可以在类上注释需要指定 @XmlAccessorType（XmlAccessType.FIELD）的字段。

You could annotate the field you need to specify @XmlAccessorType(XmlAccessType.FIELD) on the class.

@XmlRootElement(name="P1)
@XmlAccessorType(XmlAccessType.FIELD)
public class P1 {

    @XmlElement(name = "CTS")
    List<CTS> cts;

}

选项＃2 - 注释属性（获取方法）

或者你可以注释 get 方法。

@XmlRootElement(name="P1)
public class P1 {

    List<CTS> cts;

    @XmlElement(name = "CTS")
    public List<CTS> getCts() {
        return cts;
    }

}

更多信息

• http://blog.bdoughan.com/2011/06/using-jaxbs-xmlaccessortype-to.html

• http://blog.bdoughan.com/2011/06/using-jaxbs-xmlaccessortype-to.html

完整示例

CTS

您可以使用 @XmlValue 批注将Java类映射到具有简单内容的复杂类型。

You can use the @XmlValue annotation to map to Java class to a complex type with simple content.

@XmlAccessorType(XmlAccessType.FIELD)
public class CTS {

    @XmlValue
    String ct;

}

P1

import java.util.List;
import javax.xml.bind.annotation.*;

@XmlRootElement(name="P1")
@XmlAccessorType(XmlAccessType.FIELD)
public class P1 {

    @XmlElement(name = "CTS")
    List<CTS> cts;

}

演示

import java.io.File;
import javax.xml.bind.*;

public class Demo {

    public static void main(String[] args) throws Exception {
        JAXBContext jc = JAXBContext.newInstance(P1.class);

        Unmarshaller unmarshaller = jc.createUnmarshaller();
        File xml = new File("src/forum13987708/input.xml");
        P1 p1 = (P1) unmarshaller.unmarshal(xml);

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(p1, System.out);
    }

}

input.xml /输出

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<P1>
    <CTS>
        Hello
    </CTS>
    <CTS>
        World
    </CTS>
</P1>

更多信息

• http://blog.bdoughan.com/2011/06/jaxb-and-complex-types-with-simple.html

• http://blog.bdoughan.com/2011/06/jaxb-and-complex-types-with-simple.html

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