Java Time API - 获得总耗用时间的更好方法 [英] Java Time API - A better way to get total elapsed time
问题描述
这是我第一次使用Java 8中的newjava.time包。
This is my first oportunity to play with the "new" java.time package from Java 8.
我需要获得总耗用时间,例如:
1天,2小时:3米:4秒5毫米
I need to get the total elapsed time, something like:
1 day, 2h:3m:4s 5ms
我知道有2个 TemporalAmount
间隔的实施:
- 期间
年,月和日>
- 持续时间
小时,分钟,秒,毫秒和纳秒
I know that have 2 TemporalAmount
implementations for intervals:
- Period
for years, months and days
- Duration
for hours, minutes, seconds, milliseconds and nanoseconds
有一个混合这两个或者比做数学更直接的东西?
这是我迄今为止所做的最好的事情:
(更新了新的改进版本)
That was the best I could do until now: (Updated with a new improved version)
LocalDateTime start = LocalDateTime.now();
// Forcing a long time execution to measure
LocalDateTime end = start
.plusDays(1)
.plusHours(2)
.plusMinutes(3)
.plusSeconds(4)
.plusNanos(5000);
LocalDateTime elapsed = end
.minusDays(start.getDayOfYear())
.minusHours(start.getHour())
.minusMinutes(start.getMinute())
.minusSeconds(start.getSecond())
.minusNanos(start.getNano());
Period period = Period.between(start.toLocalDate(), end.toLocalDate());
long days = period.getDays();
long hours = elapsed.getHour();
long minutes = elapsed.getMinute();
long seconds = elapsed.getSecond();
long milliseconds = elapsed.getNano() / 1000;
StringBuilder msg = new StringBuilder();
msg.append(seconds);
msg.append("s ");
msg.append(milliseconds);
msg.append("ms");
if(minutes > 0) {
msg.insert(0, "m:");
msg.insert(0, minutes);
}
if(hours > 0) {
msg.insert(0, "h:");
msg.insert(0, hours);
}
if(days > 0) {
msg.insert(0, days == 1 ? " day, " : " days, ");
msg.insert(0, days);
}
System.out.println(msg.toString());
感谢您的时间=)
推荐答案
好像你需要 JodaTime
中的 PeriodFormatter
。见以下链接:
Seems like you need the PeriodFormatter
from JodaTime
. See below links:
如何格式化java中的持续时间? (例如格式H:MM:SS)
考虑到这两个,我建议使用 JodaTime
for Duration
。
Given these two, I suggest using JodaTime
for Duration
.
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