如何将双倍小数舍入到小数点后一位？ [英] How do I round a double to one decimal place?

问题描述

我想以＃格式给我一个随机的双重回复。＃然而我得到了这个效果的值：0.9395772067578356

I am trying to get a random double returned to me in the format #.# however I am getting a value of something to this effect: 0.9395772067578356

怎么做因为我不能在.nextDouble中添加参数，你只强制在随机双精度上输入一个小数。

How do you force only a one decimal return on a random double as I cannot put paraments in the .nextDouble.

        myRandomNumGenerator = new Random();
        loadedValue = myRandomNumGenerator.nextDouble();

推荐答案

DecimalFormat oneDigit = new DecimalFormat("#,##0.0");//format to 1 decimal place

System.out.println(oneDigit.format(anyVariable)); //generic usage

loadedValue = Double.valueOf(oneDigit.format(loadedValue));//specific usage posted in comments

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