XMLPullParser解析器无法解析“（??????）[????]& middot;”在xml标签内 [英] XMLPullParser parser failed to parse "(??????) [????] ·" inside xml tag

问题描述

我正在使用Jsoup解析XMLPullParser

I am parsing following XMLPullParser with Jsoup

<title>(??????) [????]0 BLACK LAGOON -???? &middot; ????- ?01-09?</title>
        <guid isPermaLink='true'>http://fenopy.eu/torrent/+black+lagoon+A+01+09+/OTcyOTA3Mw</guid>
        <pubDate>Wed, 27 Feb 2013 11:00:04 GMT</pubDate>
        <category>Anime</category>
        <link>http://fenopy.eu/torrent/+black+lagoon+A+01+09+/OTcyOTA3Mw</link>
        <enclosure url="http://fenopy.eu/torrent/-BLACK-LAGOON-01-09-/OTcyOTA3Mw==/download.torrent" length="569296173" type="application/x-bittorrent" />
        <description><![CDATA[ Category: Anime<br/>Size: 542.9 MB<br/>Ratio: 0 seeds, 3 leechers<br/> ]]></description>
        </item>

这是我的解析代码

int eventType = -1;

            while (eventType != XmlPullParser.END_DOCUMENT) {
                switch (eventType) {
                // at start of document: START_DOCUMENT
                case XmlPullParser.START_DOCUMENT:                      
                    break;

                // at start of a tag: START_TAG
                case XmlPullParser.START_TAG:
                    // get tag name
                    String tagName = parser.getName();


                    if (tagName.equalsIgnoreCase(TAG_TITLE))                            
                        String t = parser.nextText();

当我调用下一个文本时，它会抛出异常...

When I call next text and it throws following exception..

org.xmlpull.v1.XmlPullParserException: unresolved: · (position:TEXT (??????) [????] ...@36:59 in java.io.StringReader@40540698) 
at org.kxml2.io.KXmlParser.exception(KXmlParser.java:273)
at org.kxml2.io.KXmlParser.error(KXmlParser.java:269)
at org.kxml2.io.KXmlParser.pushEntity(KXmlParser.java:818)
at org.kxml2.io.KXmlParser.pushText(KXmlParser.java:849)
at org.kxml2.io.KXmlParser.nextImpl(KXmlParser.java:354)
at org.kxml2.io.KXmlParser.next(KXmlParser.java:1378)
at org.kxml2.io.KXmlParser.nextText(KXmlParser.java:1432)

推荐答案

您的xml无效。 & middot; 是xml的无效引用。

Your xml isn't valid. · is invalid reference for xml.

XML中有5个预定义的实体引用：

There are 5 predefined entity references in XML:

& lt; <小于

& gt; >大于

& amp; & &符号

& '撇号

& quot; 引号

已更新

简单使用正则表达式替换XML中的所有HTML字符

Simple use regex to replace all HTML characters from XML

XMLString.replaceAll("(&[^\\s]+?;)", ""));

这将用

这篇关于XMLPullParser解析器无法解析“（??????）[????]&amp; middot;”在xml标签内的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！