在Linux上将wstring转换为jstring [英] Converting a wstring to jstring on Linux
问题描述
我在unix中将wstring转换为jstring时出现问题,因为linux上的wchar_t的大小为4个字节(不像2个字节,因为我不能使用wchar_t转换为jchar)。
I'm having problems converting a wstring to jstring in unix, as the size of wchar_t on linux in 4 bytes (not 2 bytes like windows and thus I cannot use the casting of a wchar_t to a jchar).
任何人都可以帮助我吗?
Can anyone please help me with that?
谢谢,
Reza
Thanks, Reza
推荐答案
你必须使用类似 iconv()
的东西,因为C ++宽字符串有一个不透明的(读取:未知)编码,而Java期望UTF16。试试这个:
You have to use something like iconv()
, because C++ wide strings have an opaque (read: unknown) encoding, while Java expects UTF16. Try this:
#include <iconv.h>
#include <string>
#include <vector>
#include <iostream>
std::u16string convert(std::wstring s)
{
iconv_t cd = iconv_open("UTF-16BE", "WCHAR_T");
if (cd == iconv_t(-1))
{
std::cout << "Error while initializing iconv: " << errno << std::endl;
iconv_close(cd);
return std::u16string();
}
std::size_t n = s.length() * 2 + 1; // Each character might use up to two CUs.
const std::size_t norig = n;
std::size_t m = s.length() * sizeof(std::wstring::value_type);
std::vector<char16_t> obuf(n);
char * outbuf = reinterpret_cast<char*>(obuf.data());
const char * inbuf = reinterpret_cast<const char*>(&s[0]);
const std::size_t ir = iconv(cd, const_cast<char**>(&inbuf), &m, &outbuf, &n);
if (ir == std::size_t(-1))
{
std::cout << "Error while converting with iconv(): " << errno << ":" << EINVAL << ", left " << m
<< ", written " << std::dec << norig - n << " bytes." << std::endl;
iconv_close(cd);
return std::u16string();
}
iconv_close(cd);
return std::u16string(obuf.data(), (norig - n)/sizeof(std::u16string::value_type));
}
如果你没有 char16_t
和 std :: u16string
,你可以使用 uint16_t
作为基本字符类型和 std :: basic_string< uint16_t>
或 std :: vector< uint16_t>
作为生成的容器。
If you don't have char16_t
and std::u16string
, you can use uint16_t
as the basic character type and std::basic_string<uint16_t>
or std::vector<uint16_t>
as the resulting container.
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