我怎样才能在Android的登录/注销管理会话？ [英] How can I manage session in Android login/logout?

问题描述

我公司成功开发一个登录表单。但现在我不能够管理会议......还我已阅读多个会话concepts.but我不能这样做it.please解释我的细节。这是我的code。请帮助我怎么可以在这里使用会话的一部分。

这是我的编码部分：

 包com.androidlogin.ws;

进口org.ksoap2.SoapEnvelope;
进口org.ksoap2.serialization.PropertyInfo;
进口org.ksoap2.serialization.SoapObject;
进口org.ksoap2.serialization.SoapPrimitive;
进口org.ksoap2.serialization.SoapSerializationEnvelope;
进口org.ksoap2.transport.HttpTransportSE;
进口android.app.Activity;
进口android.os.Bundle;
进口android.view.View;
进口android.widget.Button;
进口android.widget.EditText;
进口android.widget.TextView;

 公共类AndroidLoginExampleActivity延伸活动{
 私人最终字符串NAMESPACE =htt​​p://ws.userlogin.com;
 私人最终字符串URL =htt​​p://111.223.128.10:8085/AndroidLogin/services/Login?wsdl;
私人最终字符串SOAP_ACTION =htt​​p://ws.userlogin.com/authentication;
私人最终字符串METHOD_NAME =认证;
/ **第一次创建活动时调用。 * /
@覆盖
公共无效的onCreate（包savedInstanceState）{
    super.onCreate（savedInstanceState）;
    的setContentView（R.layout.main）;
    按钮的登录=（按钮）findViewById（R.id.btn_login）;
    login.setOnClickListener（新View.OnClickListener（）{

  公共无效的onClick（查看为arg0）{
   在loginAction（）;

   }
   }）;
   }

 私人无效则loginAction（）{
 SoapObject请求=新SoapObject（命名空间METHOD_NAME）;

    EditText上的userName =（EditText上）findViewById（R.id.tf_userName）;
    。字符串USER_NAME = userName.getText（）的toString（）;
    EditText上的userPassword =（EditText上）findViewById（R.id.tf_password）;
    。字符串USER_PASSWORD = userPassword.getText（）的toString（）;

  Web服务的username变量//传递价值
    的PropertyInfo unameProp =新的PropertyInfo（）;
    unameProp.setName（username的）; //定义在Web服务方法的变量名
    unameProp.setValue（USER_NAME）; //设置username变量值
    unameProp.setType（为String.class）; //定义变量的类型
    request.addProperty（unameProp）; //通行证属性到可变

  Web服务的密码变量//传递价值
    的PropertyInfo passwordProp =新的PropertyInfo（）;
    passwordProp.setName（密码）;
    passwordProp.setValue（USER_PASSWORD）;
    passwordProp.setType（为String.class）;
    request.addProperty（passwordProp）;

    SoapSerializationEnvelope包=新SoapSerializationEnvelope（SoapEnvelope.VER11）;
    envelope.setOutputSoapObject（要求）;
    HttpTransportSE androidHttpTransport =新HttpTransportSE（URL）;

    尝试{
        androidHttpTransport.call（SOAP_ACTION，包）;
           SoapPrimitive响应=（SoapPrimitive）envelope.getResponse（）;

           TextView的结果=（TextView中）findViewById（R.id.tv_status）;
           result.setText（response.toString（））;

    }
    赶上（例外五）{

    }
   }

   }
 

解决方案

清除活性栈做的时候退出操作。

 意向意图=新的意图（这一点，LoginActivity.class）;
intent.setFlags（Intent.FLAG_ACTIVITY_CLEAR_TOP）;
startActivity（意向）;
 

然后后退按钮会留在LoginActivity活动以来堆栈被清除。 我想这会帮助你。

i successfully developed one login form. But now I am not able to manage session...also i have read more session concepts.but i can't do it.please explain me in detail. This is my code. Please help how I can use Session part here.

This is my coding part:

package com.androidlogin.ws;

import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.PropertyInfo;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import android.app.Activity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;

 public class AndroidLoginExampleActivity extends Activity {
 private final String NAMESPACE = "http://ws.userlogin.com";
 private final String URL = "http://111.223.128.10:8085/AndroidLogin/services/Login?wsdl";
private final String SOAP_ACTION = "http://ws.userlogin.com/authentication";
private final String METHOD_NAME = "authentication";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    Button login = (Button) findViewById(R.id.btn_login);
    login.setOnClickListener(new View.OnClickListener() {

  public void onClick(View arg0) {
   loginAction();

   }
   });
   }

 private void loginAction(){
 SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

    EditText userName = (EditText) findViewById(R.id.tf_userName);
    String user_Name = userName.getText().toString();
    EditText userPassword = (EditText) findViewById(R.id.tf_password);
    String user_Password = userPassword.getText().toString();

  //Pass value for userName variable of the web service
    PropertyInfo unameProp =new PropertyInfo();
    unameProp.setName("userName");//Define the variable name in the web service method
    unameProp.setValue(user_Name);//set value for userName variable
    unameProp.setType(String.class);//Define the type of the variable
    request.addProperty(unameProp);//Pass properties to the variable

  //Pass value for Password variable of the web service
    PropertyInfo passwordProp =new PropertyInfo();
    passwordProp.setName("password");
    passwordProp.setValue(user_Password);
    passwordProp.setType(String.class);
    request.addProperty(passwordProp);

    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelope.setOutputSoapObject(request);
    HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);

    try{
        androidHttpTransport.call(SOAP_ACTION, envelope);
           SoapPrimitive response = (SoapPrimitive)envelope.getResponse();

           TextView result = (TextView) findViewById(R.id.tv_status);
           result.setText(response.toString());

    }
    catch(Exception e){

    }
   }

   }

解决方案

Clear activity stack when doing logout operation.

Intent intent  = new Intent(this, LoginActivity.class);
intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
startActivity(intent);

Then back button will stay at LoginActivity since the activity stack is cleared. I guess it will help you.

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