XML修复名称空间声明 [英] XML fix namespace declaration

问题描述

我正在尝试检测/解决此错误RSS元素。
这意味着我必须找到一个错误的名称空间声明并将其
值更改为正确的名称空间。例如：

I am trying to detetct/work around this bug in RSS elements. That means I have to find a wrong namespace-declaration and change its value to the correct namespace. E.g:

xmlns:media="http://search.yahoo.com/mrss" 

必须是：

xmlns:media="http://search.yahoo.com/mrss/" 

我怎样才能获得给定一个org.w3c.Document？

How can I achive that given a org.w3c.Document?

我的意思是如何获取某个命名空间的所有元素：

I meanwile found out how to get all elements of a certain namespace:

        XPathFactory xpf = XPathFactory.newInstance();
        XPath xpath = xpf.newXPath();
        XPathExpression expr = xpath.compile("//*[namespace-uri()='http://search.yahoo.com/mrss']");


        Object result = expr.evaluate(d, XPathConstants.NODESET);
        if (result != null) {
            NodeList nodes = (NodeList) result;
            for(int node=0;node<nodes.getLength();node++)
            {
                Node n = nodes.item(node);
                this.log.warn("Found old mediaRSS namespace declaration: "+n.getTextContent());
            }

        } 

所以现在我必须搞清楚如何通过JAXP更改节点的命名空间。

So now I have to figure out how to change the namespace of a Node via JAXP.

推荐答案

仅为了完整性：

Java代码：

Document d = out.outputW3CDom(converted);
            DOMSource oldDocument = new DOMSource(d);
            DOMResult newDocument = new DOMResult();
            TransformerFactory tf = TransformerFactory.newInstance();
            StreamSource xsltsource = new StreamSource(
                    getStream(MEDIA_RSS_TRANSFORM_XSL));
            Transformer transformer = tf.newTransformer(xsltsource);
            transformer.transform(oldDocument, newDocument);

private InputStream getStream(String fileName) {
    InputStream xslStream = Thread.currentThread().getContextClassLoader()
                .getResourceAsStream("/" + fileName);
    if (xslStream == null) {
        xslStream = Thread.currentThread().getContextClassLoader()      .getResourceAsStream(fileName);
        }
        return xslStream;
    }

样式表：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <!--identity transform that will copy matched node/attribute to the output and apply templates for it's children and attached attributes-->
    <xsl:template match="node()|@*">
        <xsl:copy>
            <xsl:apply-templates select="@*|*|text()" />
        </xsl:copy>
    </xsl:template>

    <!--Specialized template to match on elements with the incorrect namespace and generate a new element-->
    <xsl:template match="//*[namespace-uri()='http://search.yahoo.com/mrss']">
        <xsl:element name="{local-name()}" namespace="http://search.yahoo.com/mrss/" >
            <xsl:apply-templates select="@*|*|text()" />
        </xsl:element>
    </xsl:template>
</xsl:stylesheet>

特别感谢Mads Hansen的帮助使用XSLT。

Special thanks to Mads Hansen for his help with the XSLT.

这篇关于XML修复名称空间声明的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！