解析并删除java正则表达式中的特殊字符 [英] Parse and remove special characters in java regex

问题描述

所以我们正在查看其他一些正则表达式帖子，我们在一个实例中删除特殊情况时遇到了问题;特殊字符位于单词的开头。

So we were looking at some of the other regex posts and we are having trouble removing a special case in one instance; the special character is in the beginning of the word.

我们的代码中有以下行：

We have the following line in our code:

String k = s.replaceAll("([a-z]+)[()?:!.,;]*", "$1");

其中s是单数字。例如，当解析句子（hi hi hi）时，通过对其进行标记，然后对每个标记执行replaceAll函数，我们得到一个输出：

where s is a singular word. For example, when parsing the sentence "(hi hi hi)" by tokenizing it, and then performing the replaceAll function on each token, we get an output of:

(hi
hi
hi

什么我们在正则表达式中是否缺少？

What are we missing in our regex?

推荐答案

您可以使用更简单的方法 - 替换您执行的字符 not 想要空格：

You can use an easier approach - replace the characters that you do not want with spaces:

String k = s.replaceAll("[()?:!.,;]+", " ");

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