带有和的Java 8 List到EnumMap [英] Java 8 List to EnumMap with sums

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本文介绍了带有和的Java 8 List到EnumMap的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有以下课程:

public class Mark {

    private Long id;

    private Student student;

    private Integer value = 0;

    private Subject subject;

}

public enum Subject {

    MATH,
    CHEMISTRY

}

我必须收到 EnumMap< Subject,Integer> ,其中value是 Mark 中所有值的总和。

列表< Mark> 的示例:

I have to receive EnumMap<Subject, Integer>, where the value is the sum of all values from the Mark.
Example of List<Mark>:


Mark(...,value = 1,subject = MATH)

Mark(。 ..,value = 2,subject = MATH)

Mark(...,value = 5,subject = CHEMISTRY)

Mark(..., value = 1, subject = MATH)
Mark(..., value = 2, subject = MATH)
Mark(..., value = 5, subject = CHEMISTRY)


$ b带有该值的$ b

我必须收到以下 EnumMap


MATH - > 3

化学 - > 5

MATH             -> 3
CHEMISTRY -> 5

我认为应该用<$ c $来完成c>收藏家:: groupingBy ,但我无法理解如何获得 EnumMap 及其价值。

I think it should be done with Collectors::groupingBy, but I can't understand how to get EnumMap and his value.

推荐答案

 markList.stream().collect(
     groupingBy(
         Mark::getSubject,
         () -> new EnumMap<Subject, Integer>(Subject.class),
         summingInt(Mark::getValue)));

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