将DEFINE翻译成char * [英] Translating a DEFINE to char*
问题描述
亲爱的人，
以下代码正在编译：
#define BUF_SZ 16383
.. ...
strcat（ConnectString，Content-Length：BUF_SZ \ n）;
但它不起作用，因为它给了我：
内容长度：BUF_SZ而不是
内容长度：16838
有办法处理这个？我想要的是在字符串中使用
中的缓冲区，但也要保持简单，并保持其灵活性。
Dear people,
The code below is compiling:
#define BUF_SZ 16383
.....
strcat(ConnectString, "Content-Length: BUF_SZ\n");
but it does not work since it give me:
Content-Length: BUF_SZ and not
Content-Length: 16838
Is there a way to handle this? What I want is to get buffersize used in
the string, but also somehow keep it simple, and keep it flexible.
推荐答案
ma*********@hotmail.com < ma*********@hotmail.com>写道：
ma*********@hotmail.com <ma*********@hotmail.com> wrote:
#define BUF_SZ 16383
....
strcat（ConnectString，" Content-Length：BUF_SZ \ n"）;
但它不起作用，因为它给了我：
内容长度：BUF_SZ而不是
内容长度：16838
有没有办法处理这个？我想要的是在字符串中使用缓冲区，但也保持简单，并保持灵活。
#define BUF_SZ 16383
....
strcat(ConnectString, "Content-Length: BUF_SZ\n");
but it does not work since it give me:
Content-Length: BUF_SZ and not
Content-Length: 16838
Is there a way to handle this? What I want is to get buffersize used in
the string, but also somehow keep it simple, and keep it flexible.
尝试snprintf（），simpe并且灵活。
-
：wq
^ X ^ Cy ^ K ^ X ^ C ^ C ^ C ^ C
ma ********* @ hotmail.com 写道：
亲爱的人们，
下面的代码正在编译：
#define BUF_SZ 16383
....
strcat（ConnectString，Content-Length：BUF_SZ \ n）;
但它不起作用，因为它给了我：
内容长度：BUF_SZ而不是
内容长度：16838
有没有办法处理这个？我想要的是在字符串中使用缓冲区，但也保持简单，并保持灵活。
Dear people,
The code below is compiling:
#define BUF_SZ 16383
....
strcat(ConnectString, "Content-Length: BUF_SZ\n");
but it does not work since it give me:
Content-Length: BUF_SZ and not
Content-Length: 16838
Is there a way to handle this? What I want is to get buffersize used in
the string, but also somehow keep it simple, and keep it flexible.
宏不在字符串中替换或者在评论中。你可以用这样的sprintf实现你想要的东西：
char my_string [BIG_ENOUGH];
sprintf （my_string，" Content-Length：％d \ nn"，BUF_SZ）;
HTH
Macros are not substituted inside strings or inside comments. You can
achieve what you want using sprintf like this:
char my_string[BIG_ENOUGH];
sprintf(my_string, "Content-Length: %d\n", BUF_SZ);
HTH
óú星期四，2006年1月5日00：38：32 -0800？ma*********@hotmail.comD'μ?>
óú Thu, 05 Jan 2006 00:38:32 -0800￡?ma*********@hotmail.comD′μ?￡o
亲爱的人们，
下面的代码是编译：
#define BUF_SZ 16383
....
strcat（ConnectString，" Content-Length：BUF_SZ \\ \
"）;
sprintf（" ConnectString，" Content-Length：％d \ n"，BUF_SZ）;
/ *
％d - int
％u - unsigned int
％s - char *
％c - char
.. ..
* /
但它不起作用，因为它给了我：
内容长度：BUF_SZ而不是
内容-Length：16838
有办法解决这个问题吗？我想要的是在字符串中使用缓冲区，但也要保持简单，并保持灵活。
Dear people,
The code below is compiling:
#define BUF_SZ 16383
....
strcat(ConnectString, "Content-Length: BUF_SZ\n"); sprintf("ConnectString, "Content-Length: %d\n",BUF_SZ);
/*
%d -- int
%u -- unsigned int
%s -- char *
%c -- char
....
*/
but it does not work since it give me:
Content-Length: BUF_SZ and not
Content-Length: 16838
Is there a way to handle this? What I want is to get buffersize used in
the string, but also somehow keep it simple, and keep it flexible.
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