将PHP翻译成Python [英] translating PHP to Python
问题描述
任何熟悉PHP的人？我正在尝试翻译。在PHP中，你可以通过以下方式获得当前对象的名称：
get_class（item）==''ClassName''
我尝试过类型（项目），但因为我不能确定我是否会在__main__
或作为子对象，我不能保证这个价值会返回什么，所以
我不能把这个值当作一个字符串来操纵。
有没有获取当前对象名称的简单方法？你会认为
__name__会起作用，对吗？它不是。
现在这里是另一个，类似的：
你可以引用一个对象的父对象直接在PHP中，如下：
//注意分号的迷人用法。不是很可爱吗？
parent :: __ construct（
$ stuffInAWeirdSyntaxThatDoesntMeanAnythingWhenYouR eadIt）;
我想要为了避免在
__init__中传递对象父元素的引用，但在Python中是否有内置的方式来说你，父母
对象，做......东西！
谢谢！
stuffInAWeirdSyntaxThatDoesntMeanAnythingWhenYouReadIt）;
我想避免在
__init__中传递对对象父级的引用，但在Python中是否存在内置方式说你，父母
对象，做......东西！
谢谢！
>有一种简单的方法来获取当前对象的名称吗？您会认为__name__会起作用，对吧？它不是。
className = item .__ class __.__ name__
我想避免在
__init__中传递对象父母的引用，但是在Python中是否有内置的方式说你，父对象，做......东西！
使用超级（）函数访问父类的属性
类C（B）：
def meth（self，arg）：
super（C，self）.meth（arg）
-Farshid
Farshid，
这是一个很好的帮助，谢谢。
第二点不会工作，因为我的意思是父母班级，
简单地说，创建当前对象的对象，*不是*当前类所基于的类。
所以，例如：
A级（对象）：
def __init __（自我）：
self.thing = Thing（）
self.thing.meth（）
def do_stuff（个体经营）：
print" S tuff"
class Thing（object）：
def meth（self）：
#now here'是我的意思想要
self.parent.do_stuff（args）
是否有内置的方法在Python中执行此操作，或者我必须传递
" parent"我什么时候开始做什么？
如果这令人困惑，很抱歉。它也让我感到困惑。我应该是一个
木匠。
- 戴夫
Anyone familiar with PHP? I''m trying to make a translation. In PHP you
can get the current object''s name by going like this:
get_class(item) == ''ClassName''
I''ve tried type(item), but since I can''t be sure if I''ll be in __main__
or as a child object, I can''t guarantee what that value will return, so
I can''t just manipulate that value as a string.
Is there a simple way to get the current object''s name? You would think
__name__ would work, right? It doesn''t.
Now here''s another, similar one:
You can reference an object''s parent object directly in PHP, like so:
//note the charming use of semi-colon. isn''t it cute?
parent::__construct(
$stuffInAWeirdSyntaxThatDoesntMeanAnythingWhenYouR eadIt);
I''d like to avoid passing a reference to an object''s parent in
__init__, but is there a built in way in Python to say "You, Parent
Object, do ...stuff!"
Thanks!
stuffInAWeirdSyntaxThatDoesntMeanAnythingWhenYouR eadIt);
I''d like to avoid passing a reference to an object''s parent in
__init__, but is there a built in way in Python to say "You, Parent
Object, do ...stuff!"
Thanks!
> Is there a simple way to get the current object''s name? You would think__name__ would work, right? It doesn''t.
className = item.__class__.__name__
I''d like to avoid passing a reference to an object''s parent in
__init__, but is there a built in way in Python to say "You, Parent
Object, do ...stuff!"
Use the super() function to access an attribute of a parent clas
class C(B):
def meth(self, arg):
super(C, self).meth(arg)
-Farshid
Farshid,
This is a great help, thanks.
The second point won''t work, though, because by parent class I mean,
simply, the object that created the current object, *not* the class the
current class is based on.
So, for example:
class A(object):
def __init__(self):
self.thing = Thing()
self.thing.meth()
def do_stuff(self):
print "Stuff"
class Thing(object):
def meth(self):
#now here''s what I WANT
self.parent.do_stuff(args)
Is there a built in way to do this in Python, or do I have to pass
"parent" when I init Thing?
Sorry if this is confusing. It confuses me, too. I should have been a
carpenter.
- Dave
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