将表格翻译成分层字典? [英] Translate a table to a hierarchical dictionary?

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问题描述

我有一张表格,其形式为:

I have a table of the form:

A1, B1, C1, (value)
A1, B1, C1, (value)
A1, B1, C2, (value)
A1, B2, C1, (value)
A1, B2, C1, (value)
A1, B2, C2, (value)
A1, B2, C2, (value)
A2, B1, C1, (value)
A2, B1, C1, (value)
A2, B1, C2, (value)
A2, B1, C2, (value)
A2, B2, C1, (value)
A2, B2, C1, (value)
A2, B2, C2, (value)
A2, B2, C2, (value)

我想在python中使用它作为字典,形式为:

I'd like to work with it in python as a dictionary, of form:

H = {
    'A1':{
        'B1':{
            'C1':[],'C2':[],'C3':[] },
        'B2':{
            'C1':[],'C2':[],'C3':[] },
        'B3':{
            'C1':[],'C2':[],'C3':[] }
    },
    'A2':{
        'B1':{
            'C1':[],'C2':[],'C3':[] },
        'B2':{
            'C1':[],'C2':[],'C3':[] },
        'B3':{
            'C1':[],'C2':[],'C3':[] }
    }
}

以便H[A][B][C]产生特定的唯一值列表.对于小型词典,我可能会像上面那样预先定义结构,但是我正在寻找一种有效的方法来遍历表并构建字典,而无需提前指定字典键.

So that H[A][B][C] yields a particular unique list of values. For small dictionaries, I might just define the structure in advance as above, but I am looking for an efficient way to iterate over the table and build a dictionary, without specifying the dictionary keys ahead of time.

推荐答案

input = [('A1', 'B1', 'C1', 'Value'), (...)]

from collections import defaultdict

tree = defaultdict(lambda: defaultdict(lambda: defaultdict(list)))
#Alternatively you could use partial() rather than lambda:
#tree = defaultdict(partial(defaultdict, partial(defaultdict, list)))

for x, y, z, value in input:
    tree[x][y][z].append(value)

这篇关于将表格翻译成分层字典?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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