如何在字典列表中找到公用键并按值对它们进行排序? [英] How to find common keys in a list of dicts and sort them by value?

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本文介绍了如何在字典列表中找到公用键并按值对它们进行排序?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想创建一个finalDic,其中包含公用密钥及其值的总和

I want to create a finalDic which contains common keys and sum of their values

myDic = [{2:1, 3:1, 5:2}, {3:4, 6:4, 2:3}, {2:5, 3:6}, ...]

首先找到公用密钥

commonkey = [{2:1, 3:1}, {2:3, 3:4}, {2:5, 3:6}]

然后求和并按值排序

finalDic= {3:11, 2,9}

我已经尝试过了,甚至没有关闭我想要的东西

I've tried this and not even close what i want

import collections

myDic = [{2:1, 3:1, 5:2}, {3:4, 6:4, 2:3}, {2:5, 3:6}]

def commonKey(x):
    i=0
    allKeys = []
    while i<len(x):
        for key in x[0].keys():
            allKeys.append(key)
        i=i+1
    commonKeys = collections.Counter(allKeys)
    commonKeys = [i for i in commonKeys if commonKeys[i]>len(x)-1]
    return commonKeys

print commonKey(myDic)

谢谢

推荐答案

这是我的处理方式:

my_dict = [{2:1, 3:1, 5:2}, {3:4, 6:4, 2:3}, {2:5, 3:6}]

# Finds the common keys
common_keys = set.intersection(*map(set, my_dict))

# Makes a new dict with only those keys and sums the values into another dict
summed_dict = {key: sum(d[key] for d in my_dict) for key in common_keys}

或者作为疯狂的单线客:

Or as a crazy one-liner:

{k: sum(d[k] for d in my_dict) for k in reduce(set.intersection, map(set, my_dict))}

这篇关于如何在字典列表中找到公用键并按值对它们进行排序?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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