什么包含.foo：{（。*）*}意味着链接脚本？ [英] What does .foo : { *(.*) } mean in a linker script?

问题描述

我正在写一个启动程序，它是512个字节，我要坚持的0xAA55将在最后2个字节我的512字节编程形象。所以我做到了。现在我的链接脚本，应该是pretty简单。我只是好奇，什么这个语法手段

I'm writing a bootable program that is 512 bytes, and I have to stick the 0xAA55 in the last 2 bytes of my 512 byte program image. So I've done that. Now my linker script, should be pretty simple. I was just curious about what this syntax means

.foo : { *(.*) }

我得到了它作为一个例子。没有.foo段，而在这之前，我改变了程序计数器

I was given it as an example. There is no .foo section, and before that, I change the program counter to

. = 0x1000 //To account for the elf header which I will strip later

所以经过这个指令

So after this directive is

.foo : { *(.*) }

这是什么呢？

推荐答案

它存储在第包含.foo 所有code，数据，BSS，rodata，等等（第二个 * 从所有目标文件（第一个）* ）的尚未分配给任何previously定义的部分。

It stores in section .foo all code, data, bss, rodata, etcetera (the second *) from all object files (the first *) that aren't yet assigned to any previously defined section.

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