如何获得一个简单的Spring MVC视图（JSP）解决方案？ [英] How to get a trivial case of Spring MVC view (JSP) resolving to work?

问题描述

我的应用程序使用Spring MVC（最新版本; 3.2.2）创建一个返回JSON的RESTful API，到目前为止我根本不需要视图层。但是现在，除了API之外，我还需要一个简单的实用程序页面（纯动态HTML），并希望使用JSP。

My app uses Spring MVC (latest; 3.2.2) to create a RESTful API returning JSON, and so far I haven't needed a view layer at all. But now, besides the API, I need a simple utility page (plain dynamic HTML) and wanted to use JSP for that.

我想要请求 http：// localhost：8080 / foo /< id> 通过控制器（Java）并最终进入JSP。应该简单吧？但我得到了404;解析视图时出现问题。

I want requests to http://localhost:8080/foo/<id> to go through a controller (Java) and end up in a JSP. Should be simple, right? But I'm getting 404; something is not right in resolving the view.

HTTP ERROR 404
Problem accessing /jsp/foo.jsp. Reason:

    Not Found

控制器：

 @RequestMapping(value = "/foo/{id}")
 public String testing(@PathVariable String id, ModelMap model) {
    model.addAttribute("id", id);
    return "foo";
 }

定义控制器和映射请求有效;调用此方法就好了。

Defining controllers and mapping requests works; this method gets called just fine.

春季配置：

<mvc:annotation-driven/>

<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"
          p:prefix="/jsp/" p:suffix=".jsp"/>

问题可能在这里。我尝试了稍微不同的前缀，并将JSP放在 WEB-INF 下，以及< mvc：view-controller path = / */> 但还没有运气。

The problem is probably here. I've experimented with slightly different prefixes and putting the JSPs under WEB-INF, as well as stuff like <mvc:view-controller path="/*" /> but no luck yet.

（我甚至需要指定InternalResourceViewResolver，还是默认视图解析器要小心这个？）

(Do I even need to specify InternalResourceViewResolver, or should default view resolvers take care of this?)

JSP文件。在 src / main / webapp / jsp 下（该项目使用Maven约定）我显然有JSP。

JSP files. Under src/main/webapp/jsp (the project uses Maven conventions) I obviously have the JSPs.

这个位置有问题吗？

web.xml ：

<servlet>
    <servlet-name>mvc-dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>mvc-dispatcher</servlet-name>
    <url-pattern>/*</url-pattern>
</servlet-mapping>

我浏览过 Spring MVC文档，但我的问题可能过于简单和明显，很容易在那里找到帮助。 :-P

I have browsed through Spring MVC documentation, but my problem is probably too trivial and obvious to easily find help there. :-P

任何人都可以告诉我我做错了什么吗？

Can anyone enlighten me on what I'm doing wrong?

推荐答案

我认为你需要做的是改变

I think what you need to do is changing

<servlet-mapping>
  <servlet-name>mvc-dispatcher</servlet-name>
  <url-pattern>/*</url-pattern>
</servlet-mapping>

到

<servlet-mapping>
  <servlet-name>mvc-dispatcher</servlet-name>
  <url-pattern>/</url-pattern>
</servlet-mapping>

/ * 如果有，则不匹配是路径中的另一个文件夹，如 /jsp/foo.jsp 。另一方面， / 将匹配所有内容。

/* won't match if there is another folder in the path, like /jsp/foo.jsp. On the other hand / will match everything.

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