创建名为'XXX'的bean时出错：通过字段'XXX'表示的不满意的依赖关系 [英] Error creating bean with name 'XXX: Unsatisfied dependency expressed through field 'XXX'

问题描述

下面是trace：

org.springframework.beans.factory.UnsatisfiedDependencyException：创建名为'testController'的bean时出错：Unsatisfied dependency通过'testDao'字段表示;嵌套的异常是org.springframework.beans.factory.BeanCreationException：创建名为'testDAO'的bean时出错：init方法的调用失败;嵌套异常是java.lang.IllegalArgumentException：不是托管类型：class modele.Test

...

原因：org.springframework.beans.factory.BeanCreationException：创建名为'testDAO'的bean时出错：init方法的调用失败;嵌套异常是java.lang.IllegalArgumentException：不是托管类型：class modele.Test

...

导致：java.lang.IllegalArgumentException：不是托管类型：class modele.Test

根据我的理解，根错误是不是托管类型：class modele.Test ，这与测试未被识别为实体有关吗？

这是我的项目：

架构： http://imgur.com/a/2xsI4

Application.java

  @SpringBootApplication 
 @ComponentScan（boot）
 @ComponentScan（dao）
 @ComponentScan（modele）
 @EnableJpaRepositories（dao）
 public class Application {
 
 public static void main（String [] args）{
 SpringApplication.run（Application.class，args）; 
} 
 
} 
  

TestDAO.java

  @Transactional 
 public interface TestDAO扩展CrudRepository< Test，Long> {
 
 / ** 
 *此方法将通过电子邮件在数据库中找到User实例。 
 *请注意，此方法未实现，其工作代码将由Spring Data JPA的签名自动生成
 *。 
 * / 
 public Test findByEmail（String email）; 
 
 $ b $ / code> 

Test.java

  @Entity 
 @Table（name =test）
 public class Test {
 
 //自动生成的id（对于db中的每个用户都是唯一的）
 @Id 
 @GeneratedValue（strategy = GenerationType.AUTO）
私有长ID; 
 
 @NotNull 
私人字符串电子邮件; 
 
 @NotNull 
私人字符串名称; 
 
 //公共方法
 
 public Test（）{
} 
 
 public Test（long id）{
 this .id = id; 
} 
 
 public Test（String email，String name）{
 this.email = email; 
 this.name = name; 
} 
 // setter和getters 
  

我很感激任何帮助。感谢！

解决方案

使用您当前的设置，您需要添加 b


  @EntityScan（modele）
  

Test 实际上并不是一个Spring Bean，它是一个 JPA实体。 @ComponentScan 寻找 @Configuration ， @Component ， @Service 和 @Repository ， @Controller 和 @RestController 。 @EntityScan 将查找实体。

您可以阅读以下内容： @EntityScan和@ComponentScan之间的区别

如果您愿意，您的配置会变得更容易： Application.java位于你的包的根目录下： com.domain.project ;

com下的存储库.domain.project.dao ;

在 com.domain.project.domain 下的实体

然后，您不需要 @EntityScan ， @ComponentScan 和 @EnableJpaRepositories ，SpringBoot将会取得com.domain.project中的所有内容。*

Below is the trace :

org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'testController': Unsatisfied dependency expressed through field 'testDao'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'testDAO': Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Not a managed type: class modele.Test

...

Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'testDAO': Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Not a managed type: class modele.Test

...

Caused by: java.lang.IllegalArgumentException: Not a managed type: class modele.Test

From my understanding the root error is Not a managed type: class modele.Test, which would have something to do with Test not being recognized as an entity ?

Here's my project :

Architecture : http://imgur.com/a/2xsI4

Application.java

@SpringBootApplication
@ComponentScan("boot")
@ComponentScan("dao")
@ComponentScan("modele")
@EnableJpaRepositories("dao")
public class Application {

    public static void main (String[] args){
        SpringApplication.run(Application.class, args);
    }

}

TestDAO.java

@Transactional
public interface TestDAO extends CrudRepository<Test, Long > {

  /**
   * This method will find an User instance in the database by its email.
   * Note that this method is not implemented and its working code will be
   * automagically generated from its signature by Spring Data JPA.
   */
  public Test findByEmail(String email);

}

Test.java

@Entity
@Table(name = "test")
public class Test {

    // An autogenerated id (unique for each user in the db)
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private long id;

    @NotNull
    private String email;

    @NotNull
    private String name;

    // Public methods

    public Test() {
    }

    public Test(long id) {
        this.id = id;
    }

    public Test(String email, String name) {
        this.email = email;
        this.name = name;
    }
//setters and getters

I'd appreciate any help. Thanks!

解决方案

With your current setup, you need to add

@EntityScan("modele")

Test isn't really a Spring Bean per say, it's a JPA Entity. @ComponentScan looks for @Configuration, @Component, @Service and @Repository, @Controller and @RestController. @EntityScan will look for Entities.

You can read this: Difference between @EntityScan and @ComponentScan

Your configuration would be much easier if you'd move :

• Application.java at the root of your packages: com.domain.project;
• your repositories under com.domain.project.dao;
• your entities under com.domain.project.domain.

Then, you wouldn't need @EntityScan, @ComponentScan and @EnableJpaRepositories, SpringBoot will just pickup everything found in com.domain.project.*

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