难以使用Envers审核多对多关系 [英] Having difficulty using Envers to audit a many-to-many relation

问题描述

我想使用Envers来审计与嵌入式组件的多对多关系，但是我遇到了一个MappingException，说不支持ComponentType。这是堆栈跟踪的相关部分：

I'm wanting to use Envers to audit a many-to-many relation with an embedded component but I'm having trouble with a MappingException saying the the ComponentType is not supported. This is relevant portion of the stack trace:

Caused by: org.hibernate.MappingException: Type not supported: org.hibernate.type.ComponentType
        at org.hibernate.envers.configuration.metadata.IdMetadataGenerator.addIdProperties(IdMetadataGenerator.java:74)
        at org.hibernate.envers.configuration.metadata.IdMetadataGenerator.addId(IdMetadataGenerator.java:105)
        at org.hibernate.envers.configuration.metadata.AuditMetadataGenerator.generateFirstPass(AuditMetadataGenerator.java:413)
        at org.hibernate.envers.configuration.EntitiesConfigurator.configure(EntitiesConfigurator.java:101)
        at org.hibernate.envers.configuration.AuditConfiguration.<init>(AuditConfiguration.java:103)
        at org.hibernate.envers.configuration.AuditConfiguration.getFor(AuditConfiguration.java:135)
        at org.hibernate.envers.event.EnversIntegrator.integrate(EnversIntegrator.java:63)
        at org.hibernate.internal.SessionFactoryImpl.<init>(SessionFactoryImpl.java:295)
        at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1737)
        at org.hibernate.ejb.EntityManagerFactoryImpl.<init>(EntityManagerFactoryImpl.java:76)
        at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:905)

阅读Envers参考，似乎Envers可以处理
我正在尝试做的事情。根据参考：

Reading the Envers reference, it appears that Envers can handle what I'm trying to do. According to the reference:

如果您想覆盖从@Mappedsuperclass或嵌入式组件继承的某些字段/属性的审核行为，您可以在组件的子类型或使用网站上应用@AuditOverride（s）注释。

If you'd like to override auditing behaviour of some fields/properties inherited from @Mappedsuperclass or in an embedded component, you can apply the @AuditOverride(s) annotation on the subtype or usage site of the component.

这是我的关联实体。您可以在类级别查看我尝试使用@AuditOverride的位置，以防止审核嵌入式组件。我也尝试在字段本身上使用注释。两者都没有区别。

Here's my association entity. You can see where I tried to use @AuditOverride at the class level to prevent auditing the embedded component. I also tried using the annotation on the field itself. Neither made a difference.

@Audited
//  @AuditOverride(name = "pk", isAudited = false) <===== Didn't help
@Table(name = "user_role")
@javax.persistence.Entity
@AssociationOverrides
(
    {
    @AssociationOverride
        (name = "pk.user", joinColumns = @JoinColumn(name = "id")),
    @AssociationOverride
        (name = "pk.role", joinColumns = @JoinColumn(name = "id"))
    }
)
public class UserRole extends Entity<UserRole>
{
    private static final long serialVersionUID = 1L;

    private Date expirationDate;
    private UserRolePk pk = new UserRolePk();

    public UserRole() {}

    //  @AuditOverride(name = "pk", isAudited = false) <== Didn't help
    @EmbeddedId
    public UserRolePk getPk() { return pk; }

    @Transient
    public User getUser() { return getPk().getUser(); }

    @Transient
    public Role getRole() { return getPk().getRole(); }
...
}

这是用户实体：

@Audited
@Table(name = "applicationuser")
@javax.persistence.Entity
public class User extends Entity<User>
{
    private static final long serialVersionUID = 1L;
    private String firstName;
    private String lastName;
    private String email;
    private Set<UserRole> userRoles = new HashSet<UserRole>(0);

    @OneToMany(fetch = FetchType.LAZY, cascade=CascadeType.ALL,
        mappedBy = "pk.user", orphanRemoval = true)

    public Set<UserRole> getUserRoles() { return userRoles; }
...
}

这是角色实体：

@Audited
@Table(name = "role")
@javax.persistence.Entity
public class Role extends Entity<Role>
{
    private static final long serialVersionUID = 1L;
    private String name;
    private String label;
    private Set<UserRole> userRoles = new HashSet<UserRole>(0);

    @OneToMany(fetch = FetchType.LAZY, mappedBy = "pk.role",
        cascade=CascadeType.ALL, orphanRemoval = true)

    public Set<UserRole> getUserRoles() { return userRoles; }
...
}

这是嵌入式组件：

@Embeddable
public class UserRolePk implements Serializable
{
    private static final long serialVersionUID = 1L;

    private User user;
    private Role role;

    @ManyToOne
    public User getUser() { return user; }

    @ManyToOne
    public Role getRole() { return role; }
...
}

最后，这是我的基本实体，为了完整性：

And finally, here is my base entity, for completeness:

@MappedSuperclass()
public abstract class Entity<X extends Entity<X>>
    implements Comparable<X>, Serializable
{
    private static final long serialVersionUID = 1L;
    private Long id;
    private Timestamp timestamp;
...
}

我已阅读Envers参考资料并仔细阅读论坛，但信息
似乎很稀疏。关于这个的任何想法或指示？

I've read the Envers reference and perused the forum, but the information seems pretty sparse. Any ideas or pointers on this?

推荐答案

我通过丢弃可嵌入组件UserRolePk来解决这个问题，并且只是使用@JoinColumn例如

I resolved this by discarding the embeddable component, UserRolePk, and just going with @JoinColumn e.g.

public class UserRole extends Entity<UserRole>
{
    private User user;
    private Role role;

    public UserRole() {}

    @ManyToOne(fetch=FetchType.EAGER, optional=false)
    @JoinColumn(name="userid", referencedColumnName = "id", insertable=false, updatable=false)
    // XmlTransient used to prevent the following exception when JAXB marshals this into XML:
    //  com.sun.istack.SAXException2: A cycle is detected in the object graph. This will cause
    //  infinitely deep XML:
    @XmlTransient
    public User getUser() { return this.user; }

    @ManyToOne(fetch=FetchType.EAGER, optional=false)
    @JoinColumn(name="roleid", referencedColumnName = "id", insertable=false, updatable=false)
    public Role getRole() { return this.role; }
...
}

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