如何通过从JavaFX 2中的ListView中选择项来执行操作 [英] How to perform an action by selecting an item from ListView in JavaFX 2

问题描述

我希望在javafx 2中从 listview 中选择一个项目时执行操作。
我使用Netbeans JavaFX fxml应用程序和SceneBuilder。
SceneBuilder中的 OnMouseClicked 方法不起作用。它给了我一个错误，它无法找到我已经声明的方法。

I would like to have an action performed when I select an item from my listview in javafx 2. I use a Netbeans JavaFX fxml application and SceneBuilder. The OnMouseClicked method in SceneBuilder did not work. It gave me back an error that it can't find the method that I have already declared.

有人能告诉我他们是如何设法让它工作的吗？

Can someone tell me how they managed to get it to work?

推荐答案

你不能单独在FXML文件中这样做。

定义相应的listView（假设 fx：id =myListView（FXML）：

You cannot do it in FXML file alone.
Define the corresponding listView (assuming fx:id="myListView" in FXML) in Controller class of the FXML file:

@FXML
private ListView<MyDataModel> myListView;

在init / start方法中添加监听器，它将监听列表视图项的变化：

Add listener in init/start method which will listen to the list view item changes:

myListView.getSelectionModel().selectedItemProperty().addListener(new ChangeListener<MyDataModel>() {

    @Override
    public void changed(ObservableValue<? extends MyDataModel> observable, MyDataModel oldValue, MyDataModel newValue) {
        // Your action here
        System.out.println("Selected item: " + newValue);
    }
});

MyDataModel 可以是您自己的数据结构模型类或只是字符串。

对于字符串示例，

MyDataModel can be your own data structure model class or simply a String.
For String example,

@FXML
private ListView<String> myListView;

...
...

ObservableList<String> data = FXCollections.observableArrayList("chocolate", "blue");
myListView.setItems(data);

myListView.getSelectionModel().selectedItemProperty().addListener(new ChangeListener<String>() {
    @Override
    public void changed(ObservableValue<? extends String> observable, String oldValue, String newValue) {
        // Your action here
        System.out.println("Selected item: " + newValue);
    }
});

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