Android的获取字符串返回从AsyncTask的 [英] Android getting string back from AsyncTask

问题描述

我有创建了以下类：

public class getURLData extends AsyncTask<String, Integer, String>{

@Override
protected String doInBackground(String... params) {
    String line;
    try {  
        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpPost httpPost = new HttpPost(params[0]);

        HttpResponse httpResponse = httpClient.execute(httpPost);
        HttpEntity httpEntity = httpResponse.getEntity();
        line = EntityUtils.toString(httpEntity);

    } catch (UnsupportedEncodingException e) {
        line = "<results status=\"error\"><msg>Can't connect to server</msg></results>";
    } catch (MalformedURLException e) {
        line = "<results status=\"error\"><msg>Can't connect to server</msg></results>";
    } catch (IOException e) {
        line = "<results status=\"error\"><msg>Can't connect to server</msg></results>";
    }
    return line;
}

@Override
protected void onPostExecute(String result) {
    super.onPostExecute(result);
}

}

我想调用它像这样：

I am trying to call it like so:

String output = null;
output = new getURLData().execute("http://www.domain.com/call.php?locationSearched=" + locationSearched);

但是，输出变量是没有得到数据，而不是我得到一个错误：

But the output variable isn't getting data, instead I am getting an error:

Type mismatch: cannot convert from AsyncTask<String,Integer,String> to String

请帮忙

推荐答案

方法执行返回 AynscTask 本身，你需要调用 GET ：

The method execute returns the AynscTask itself, you need to call get:

output =
    new getURLData()
        .execute("http://www.domain.com/call.php?locationSearched=" + locationSearched)
        .get();

不过，如果你这样做，你只要把你的异步的任务成的同步的一个，因为 GET 等待如果需要的结果是即时拍摄

However, if you do that you just turned your async task into a sync one, as get waits if needed for the result to be avilable.

参考：<一href="http://developer.android.com/reference/android/os/AsyncTask.html#get%28%29">AsyncTask.get

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