正则表达式分裂骆驼案 [英] Regex to split camel case

问题描述

我在JavaScript中有一个正则表达式，使用以下代码将我的驼峰字符串字符串拆分为大写字母（我后来从 here ）：

I have a regular expression in JavaScript to split my camel case string at the upper-case letters using the following code (which I subsequently got from here):

"MyCamelCaseString"
    .replace(/([A-Z])/g, ' $1')
    .replace(/^./, function(str){ return str.toUpperCase(); })

因此返回：

"My Camel Case String"

这很好。但是，我想把它提升一个档次。有人可以用一个正则表达式来帮助我，只有当前一个字符是小写且后者是大写时才会分裂。

Which is good. However, I want to step this up a notch. Could someone help me with a regex which will split if, and only if, the former character is lower-case and the latter is upper-case.

因此，以上示例将是我期望的结果，但如果我这样做：

Thus, the above example will be the result I expect, but if I do:

"ExampleID"

然后我回来了：

"Example ID"

而不是

"Example I D"

因为它在每个大写字母中分裂并忽略它之前的任何内容。

Since it's splitting at each upper-case and ignoring anything before it.

希望这有意义！谢谢:)。

Hope that makes sense! And thanks :).

推荐答案

我的猜测是替换 /（[AZ]）/ 带 /（[az]）（[AZ]）/ 和'$ 1'带'$ 1 $ 2'

My guess is replacing /([A-Z])/ with /([a-z])([A-Z])/ and ' $1' with '$1 $2'

"MyCamelCaseString"
    .replace(/([a-z])([A-Z])/g, '$1 $2');

/（[a-z0-9]）（[AZ]） / 用于计算小写字符的数字

/([a-z0-9])([A-Z])/ for numbers counting as lowercase characters

console.log("MyCamelCaseStringID".replace(/([a-z0-9])([A-Z])/g, '$1 $2'))

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