从字符串数组随机元素 [英] Random element from string array
问题描述
我有一个字符串数组：
String[] fruits = {"Apple","Mango","Peach","Banana","Orange","Grapes","Watermelon","Tomato"};
和我收到的随机元素从这个方式：
and i am getting random element from this by:
String random = (fruits[new Random().nextInt(fruits.length)]);
现在我想在这苹果是present当我按下按钮来获得随机水果的数量，就像当我preSS randon按钮，它给了我Banana..and也应该给我的元素号码是 3
now i want to get the number at which apple is present when i hit the button to get random fruit, like when i press randon button it gives me Banana..and also should give me that element number is 3
我得到的元素，但有问题，得到元素数目，所以请帮助我
I get the element but have problem getting the element number, so please help me out
推荐答案
只是存储在一个变量生成的索引，然后使用该varaible访问数组：
Just store the index generated in a variable, and then access the array using this varaible:
int idx = new Random().nextInt(fruits.length);
String random = (fruits[idx]);
P.S。我平时不喜欢每randoization产生新的随机对象 - 我在使用单个随机 preFER方案 - 并重新使用它。它可以让我轻松地再现问题的顺序，如果我以后发现程序中的错误。
P.S. I usually don't like generating new Random object per randoization - I prefer using a single Random in the program - and re-use it. It allows me to easily reproduce a problematic sequence if I later find any bug in the program.
根据这种方法，我都会有一些变量随机ř的地方，我将只使用：
According to this approach, I will have some variable Random r somewhere, and I will just use:
int idx = r.nextInt(fruits.length)
不过，你的做法是正常的，但是你可能很难再现特定的顺序，如果你需要稍后。
However, your approach is OK as well, but you might have hard time reproducing a specific sequence if you need to later on.
这篇关于从字符串数组随机元素的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
