kotlin从数组中获取随机字符串 [英] kotlin Get random string from array

问题描述

kotlin的新知识和很多问题和答案，大部分是Java语言.在遵循文档并针对众多SO进行验证后，问题/答案 Android Studio抱怨关于以下功能.功能是

New to kotlin and quite a few questions and answers, mostly in Java. After following the documentation and verifying against numerous SO questions/answers Android Studio is complaining about the following in a function. The function is

fun getRandomQuote() {
    val randomValue = Random.nextInt(quotes.size)
    //return quotes[randomValue]
    return quotes.get(randomValue)
}

引号是arrayOf(strings)

quotes is an arrayOf(strings)

val quotes = arrayOf("Alert today – Alive tomorrow.",...)

说

quotes.get(randomValue)

应该是一个 Unit ，但是找到了 String .randomValue应该是文档使用nextInt，除非我误解了文档.我没有看到这个问题.我只是想从数组中随机返回一个字符串.我以为可能是工作室的另一个误报，所以我清理了项目，但在此停止建设.有人看到我在做什么错了.

That it should be a Unit but found String. randomValue should be an integer as defined by the docs using nextInt unless I misinterpreted the docs. I don't see the issue. I'm just trying to randomly return a string from the array. I thought maybe another false positive from studio so I cleaned the project but it stops here on building. Anyone see what it is I'm doing wrong.

推荐答案

您的函数未指定返回类型，这就是为什么编译器期望'Unit'与Java中的void相同的原因.

Your function doesn't specify a return type, that's why the compiler is expecting 'Unit' which would be the same as void in Java.

要返回字符串时，需要像这样指定它

When you want to return a String, you need to specify it like so

fun getRandomQuote(): String {
    val randomValue = Random.nextInt(quotes.size)
    return quotes[randomValue]
}

请参阅文档以获取 Kotlin函数作为参考.

See the docs for Kotlin functions as a reference.

将索引用于带方括号的数组而不是get()函数也更容易.

It is also more kotliny to use indexing for arrays with square brackets instead of get() function.

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