我怎么可以转换UNI code字符串在Java中为ASCII [英] how can I convert unicode string to ASCII in java

问题描述

我现在想转换UNI code字体在Android中使用ASCII。我写了下面的编码转换UNI code字体为ascii，但它的失败。因为结果不能被转换后的正常显示。

UNI code字型='ေနေကာင္းပါသလား喜欢的东西'\ u100F \ u1039 \ u100D'

 公共静态字符串toJAVA（字符串zawgyi）{
    字符串输出=;
    的char [] charArray = zawgyi.toCharArray（）;

    的for（int i = 0; I＆LT; charArray.length;我++）{
        所以char a = charArray [I]
        如果（（int）的a取代; 255）{
            输出+ =\\ U+ Integer.toHexString（（INT）一）+ - ;
        } 其他 {
            输出+ =一个;
        }
    }
    返回输出;
}
 

解决方案

使用java.text.Normalizer类从单向code转换为ASCII。这里距离答案样本code http://stackoverflow.com/a/2097224/931982

 的String =口水鸡喂了;

字符串S1 = Normalizer.normalize（S，Normalizer.Form.NFKD）;
字符串的正则表达式= Pattern.quote（[\\ p {InCombiningDiacriticalMarks} \\ p {} ISLM \\ p {IsSk}] +）;

字符串s2 =新的String（s1.replaceAll（正则表达式，）.getBytes（ASCII），ASCII）;

的System.out.println（S2）;
的System.out.println（s.length（）== s2.length（））;
 

I'm now trying to convert unicode font to ascii in android. I wrote following coding to convert unicode font to ascii but it's failed. Because result cannot display properly after being converted.

unicode font = 'ေနေကာင္းပါသလား' to something like '\u100F\u1039\u100D'

public static String toJAVA (String zawgyi) {
    String output = "";
    char[] charArray = zawgyi.toCharArray();

    for (int i = 0; i < charArray.length; i++) {
        char a = charArray[i];
        if ((int) a > 255) {
            output += "\\u" + Integer.toHexString((int) a) + "--";
        } else {
            output += a;
        }
    }       
    return output;
}

解决方案

use java.text.Normalizer class to convert from unicode to ascii. here is a sample code from the answer http://stackoverflow.com/a/2097224/931982

String s = "口水雞 hello Ä";

String s1 = Normalizer.normalize(s, Normalizer.Form.NFKD);
String regex = Pattern.quote("[\\p{InCombiningDiacriticalMarks}\\p{IsLm}\\p{IsSk}]+");

String s2 = new String(s1.replaceAll(regex, "").getBytes("ascii"), "ascii");

System.out.println(s2);
System.out.println(s.length() == s2.length());

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