我怎么能转换的Uni code路径C字符串？ [英] How can I convert a Unicode path to a c string?

问题描述

我如何从一个统一code路径名（LPWSTR）转换成等价的ASCII码？被调用的库只能理解C字符串。

编辑：
好吧，我把GetShortPathName和调用WideCharToMultiByte建议，并创建了一张code，我含在路径的Uni code字符一些文件夹测试，它完美地工作：

  wlength = GetShortPathNameW（CPY，0,0）;
LPWSTR SHORTP =（LPWSTR）释放calloc（wlength，sizeof的（WCHAR））;
GetShortPathNameW（CPY，SHORTP，wlength）;
clength =调用WideCharToMultiByte（CP_OEMCP，WC_NO_BEST_FIT_CHARS，SHORTP，wlength，0，0，0，0）;
LPSTR CPATH =（LPSTR）释放calloc（clength，sizeof的（CHAR））;
调用WideCharToMultiByte（CP_OEMCP，WC_NO_BEST_FIT_CHARS，SHORTP，wlength，CPATH，clength，0，0）;
 

解决方案

GetShortPathName（）功能

http://msdn.microsoft.com/ EN-US /库/ aa364989％28VS.85％29.aspx

会给你一个等效8.3文件名，指向同一个文件中，与传统code使用。

这可能是你能做的最好的，虽然理论上的8.3文件名可能包含非ASCII字符，这取决于注册表设置。在这种情况下，你没有得到适当的char *一个简单的方法，和GetShortPathNameA（）将不会做，要么如果文件创建时codePAGE设置不匹配当前设置。

请参阅 http://technet.microsoft.com /en-us/library/cc781607%28WS.10%29.aspx 有关的设置。有一个concensus这里（见下文），这起案件是合理的忽视。

由于伦，一切为这个职位的贡献。

How can i convert from a Unicode path name (LPWSTR) to the ASCII equivalent? The library that gets called understands only c strings.

Edit: Okay, I took the GetShortPathName and the WideCharToMultiByte suggestions and created that piece of code, i tested it with some folders containing Unicode characters in the path and it worked flawlessly:

wlength = GetShortPathNameW(cpy,0,0);
LPWSTR shortp = (LPWSTR)calloc(wlength,sizeof(WCHAR));
GetShortPathNameW(cpy,shortp,wlength);
clength = WideCharToMultiByte(CP_OEMCP, WC_NO_BEST_FIT_CHARS, shortp, wlength, 0, 0, 0, 0);
LPSTR cpath = (LPSTR)calloc(clength,sizeof(CHAR));
WideCharToMultiByte(CP_OEMCP, WC_NO_BEST_FIT_CHARS, shortp, wlength, cpath, clength, 0, 0);

解决方案

GetShortPathName() Function

http://msdn.microsoft.com/en-us/library/aa364989%28VS.85%29.aspx

Will give you an equivalent 8.3 filename, pointing to the same file, for use with legacy code.

[EDIT] This is probably the best you can do, although theoretically the 8.3 filenames may contain non-ascii characters, depending on registry setting. In this case, you don't have an easy way of getting the proper char*, and GetShortPathNameA() will not do that either if codepage setting during file creation does not match current setting.

See http://technet.microsoft.com/en-us/library/cc781607%28WS.10%29.aspx about the setting. There's a concensus here (see below) that this case is reasonable to neglect.

Thanks Moron, All, for contribution to this post.

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