为什么JavaScript没有严格大于/小于比较运算符？ [英] Why doesn't JavaScript have strict greater/less than comparison operators?

问题描述

虽然JavaScript的类型严格比较运算符（ === ，！== ）很好，但它没有没有相应的严格比较大于/小于。

While JavaScript's type-strict comparison operators (===, !==) are nice, it doesn't have corresponding strict comparisons for greater/less than.

var x = 10;

x <= 20;    // true
x <= '20';    // true
x <== 20;   // true (or would be, if JS had such an operator)
x <== '20'; // false (ditto)

为什么不呢？我问这个问题充分期待答案是呃，因为它没有，但无论如何我都要问，以防这些操作符被忽略有一个有趣和/或令人沮丧的历史原因。

Why not? I ask this question fully expecting the answer to be "uh, because it doesn't", but I'm asking anyway, in case there's an interesting and/or disheartening historical reason for such operators being omitted.

推荐答案

我只能猜测 -

如果

a === b 为假，然后

a！== b 为真。的 总是 即可。

If
a === b is false, then
a !== b is true. always.

但是，这种含义不适用于< ==

But, this implication wouldn't hold for <==

如果

x< == 20 为false，我们无法推断
<$ c $的结果c> x> == 20 因为类型检查或关系检查可能是假的。

If
x <== 20 is false, we cannot infer the result of x >== 20 because it might have been false due to type check, or the relation check.

我认为这是<虽然语言中有很多东西要糟糕得多（一般来说类型强制，但要说出一个）。

I think that's slightly confusing, although there's plenty of things in the language that are much worse (type coercion in general, to name one).

然而，我认为严格的< 或> 会表现一致。

However, I think a strict < or > would behave consistently.

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