为什么C ++没有幂运算符? [英] Why doesn't C++ have a power operator?

问题描述

许多语言都有幂运算符；为什么C ++没有?例如，Fortran和Python使用**，并且通常使用^编写(例如，在LaTeX中).

Many languages have a power operator; why doesn't C++? For example, Fortran and Python use ** and is commonly written (in LaTeX, for example) using ^.

推荐答案

C ++确实具有幂运算符—编写为pow(x, y).

C++ does have a power operator—it's written pow(x, y).

最初，C在设计时就考虑了系统软件，并且 不需要动力操作员. (但它有 &和|之类的按位运算符 其他语言.)有人在讨论添加一种 在C ++标准化期间，但最终共识是更多 或更少:

Originally, C was designed with system software in mind, and there wasn't much need for a power operator. (But it has bitwise operators, like & and |, which are absent in a lot of other languages.) There was some discussion of adding one during standardization of C++, but the final consensus was more or less:

• 它不能是^，因为优先级是错误的(以及 当然，具有2. ^ 8 == 256.，但是2 ^ 8 == 10不是很 要么愉快).

• It couldn't be ^, because the priority was wrong (and of course, having 2. ^ 8 == 256., but 2 ^ 8 == 10 isn't very pleasant either).

不能为**，因为那样会破坏现有的 程序(可能具有x**p之类的内容，其中x和 int和p和int*).

It couldn't be **, because that would break existing programs (which might have something like x**p, with x an int, and p an int*).

可能是*^，因为此序列当前不合法 在C或C ++中.但这仍然需要引入 其他优先级.

It could be *^, because this sequence isn't currently legal in C or C++. But this would still require introducing an additional level of precedence.

C和C ++已经具有足够的特殊标记和级别的 优先事项，以及与数字社区的讨论之后， 得出的结论是，确实没有任何问题 pow(x, y).

C and C++ already had enough special tokens and levels of precedence, and after discussions with the numerics community, it was concluded that there really wasn't anything wrong with pow(x, y).

因此C ++保持原样，这似乎没有 造成了任何问题.

So C++ left things as they were, and this doesn't seem to have caused any problems.

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