为什么 C# 中没有 ||= 或 &&= 运算符? [英] Why are there no ||= or &&= operators in C#?

问题描述

对于所有逻辑运算符、移位运算符、加法运算符和所有乘法运算符，我们都有等效的赋值运算符.

We have equivalent assignment operators for all Logical operators, Shift operators, Additive operators and all Multiplicative operators.

为什么逻辑运算符被遗漏了?有什么好的技术原因为什么很难吗?

Why did the logical operators get left out? Is there a good technical reason why it is hard?

推荐答案

为什么逻辑运算符被遗漏了?有什么好的技术原因为什么很难吗?

Why did the logical operators get left out? Is there a good technical reason why it is hard?

他们没有.如果需要，您可以执行 &= 或 |= 或 ^= .

They didn't. You can do &= or |= or ^= if you want.

bool b1 = false;
bool b2 = true;
b1 |= b2; // means b1 = b1 | b2

|| 和 && 运算符没有复合形式，因为坦率地说，它们有点傻.在什么情况下你想说

The || and && operators do not have a compound form because frankly, they're a bit silly. Under what circumstances would you want to say

b1 ||= b2;
b1 &&= b2;

这样，如果左侧不改变，则不会评估右侧?似乎只有少数人会真正使用此功能，为什么要添加它?

such that the right hand side is not evaluated if the left hand side does not change? It seems like only a few people would actually use this feature, so why put it in?

有关复合运算符的更多信息，请参阅我的严肃文章:
https://docs.microsoft.com/en-us/archive/blogs/ericlippert/compound-assignment-part-one

For more information about the compound operators, see my serious article here:
https://docs.microsoft.com/en-us/archive/blogs/ericlippert/compound-assignment-part-one

以及这里的后续愚人节文章:
https://docs.microsoft.com/en-us/archive/blogs/ericlippert/compound-assignment-part-two

and the follow-up April-Fools article here:
https://docs.microsoft.com/en-us/archive/blogs/ericlippert/compound-assignment-part-two

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