&有什么区别？和&& C＃中的运算符 [英] What is the difference between & and && operators in C#

问题描述

我试图理解C＃中& 与& 运算符之间的区别。我在互联网上搜索失败。有人可以举个例子吗？

I am trying to understand the difference between & and &&operators in C#. I searched on the internet without success. Can somebody please explain with an example?

推荐答案

& 是按位AND运算符。对于整数类型的操作数，它将计算操作数的按位与，结果将是整数类型。对于布尔操作数，它将计算逻辑和。 & 是逻辑AND运算符，不适用于整数类型。对于可以同时使用这两种类型的布尔类型，区别在于&& 的短路属性。如果& 的第一个操作数求值为 false ，则第二个则根本不求值。 & 不是这种情况：

& is the bitwise AND operator. For operands of integer types, it'll calculate the bitwise-AND of the operands and the result will be an integer type. For boolean operands, it'll compute the logical-and of operands. && is the logical AND operator and doesn't work on integer types. For boolean types, where both of them can be applied, the difference is in the "short-circuiting" property of &&. If the first operand of && evaluates to false, the second is not evaluated at all. This is not the case for &:

 bool f() {
    Console.WriteLine("f called");
    return false;
 }
 bool g() {
    Console.WriteLine("g called");
    return false;
 }
 static void Main() {
    bool result = f() && g(); // prints "f called"
    Console.WriteLine("------");
    result = f() & g(); // prints "f called" and "g called"
 }

|| 与该属性中的&& 类似；

|| is similar to && in this property; it'll only evaluate the second operand if the first evaluates to false.

当然，用户定义的类型可以使这些运算符超载，从而使其可以执行所需的任何操作。

Of course, user defined types can overload these operators making them do anything they want.

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