JQuery将函数返回给变量 [英] JQuery return a function to a variable

问题描述

有没有办法设置一个等于函数的变量，而不是变量等于函数它等于函数返回值？

Is there any way to set a variable equal to a function, but instead of the variable being equal to the function it is equal to the functions return value?

搜索了一下这一点没有任何成功，很可能是因为我不知道如何表达问题，但任何帮助都表示赞赏，这就是我所拥有的：

Searched for a bit on this without any success, it is most likely because I don't know how to phrase the question, but any help is appreciated, this is what I have :

在函数之后不必设置 var ztype = zoom（），无论如何我都要将返回值赋给 zoom 没有多行代码？

Instead of having to set var ztype = zoom() after the function, is there anyway for me to assign the return value to zoom without an extra line of code?

var zoom = function(){ //can be set to Full / percentage / Image / left empty for native image size
    var type = $('.carousel').attr('data-zoom');
    if(!type){
        type = $(that).attr('data-zoom');
    }

    return type;
}
var ztype = zoom();

推荐答案

如果我理解你的话，你就是试图将变量设置为函数的结果。这应该做你希望的;

If I'm understanding you correctly, you're trying to set a variable to the result of a function. This should do what you're hoping for;

var ztype = function(){ //can be set to Full / percentage / Image / left empty for native image size
    var type = $('.carousel').attr('data-zoom');
    if(!type){
        type = $(that).attr('data-zoom');
    }

    return type;
}();

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