将Javascript变量返回给AppleScript [英] Return Javascript variable to AppleScript

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本文介绍了将Javascript变量返回给AppleScript的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

所以,我有一个在AppleScript中可能无法实现的简单问题。我试图从代码中没有返回的javascript返回一个变量。换句话说,我试图获取元素的状态,以便我可以有条件地运行一个函数。这是我得到的代码,不会得到回报:

So, I have a simple problem which may not be possible in AppleScript. I'm attempting to return a variable from a javascript that doesn't have a return in the code. In other words, I'm trying to get the status of an element so that I can run a function conditionally. Here is the code I have that will not get a return:

tell application "Safari"
    activate
    open location "http://127.0.0.1:9999"
    delay 1
    set myVar to do JavaScript "var obj = document.getElementById(87); myVar = obj.value; return myVar;" in document 1
    return myVar
end tell

所以,基本上我是试图获取 obj 的值并将其返回到AppleScript,它应该在0到255之间(它是一个按钮)。问题是,我对javascript函数没有任何控制权,所以我无法添加 return obj.value 。这可能吗?

So, basically I'm trying to get the value of obj and return it to AppleScript, which should be between 0 and 255 (it's a button). The problem is, I don't have any control over the javascript function so I can't add a return obj.value. Is this possible?

推荐答案

删除return以及var。 do JavaScript将返回最后的全局值。例如,这应该返回7.0:

Remove the "return" as well as the "var". "do JavaScript" will return the last global value. This, for example, should return 7.0:

tell application "Safari"
    activate
    open location "http://www.hoboes.com/Mimsy/"
    delay 1
    set myVar to do JavaScript "numbervalue=3;fred=numbervalue+4" in document 1
    return myVar
end tell

然而,这应该返回3.0,因为那是最后的全局值:

This, however, should return 3.0, as that’s the last global value:

tell application "Safari"
    activate
    open location "http://www.hoboes.com/Mimsy/"
    delay 1
    set myVar to do JavaScript "numbervalue=3; var fred=numbervalue+4" in document 1
    return myVar
end tell

这篇关于将Javascript变量返回给AppleScript的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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