将 Javascript 变量返回到 AppleScript [英] Return Javascript variable to AppleScript

查看:30
本文介绍了将 Javascript 变量返回到 AppleScript的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

所以,我有一个简单的问题,这在 AppleScript 中可能是不可能的.我正在尝试从代码中没有返回的 javascript 返回一个变量.换句话说,我正在尝试获取元素的状态,以便我可以有条件地运行函数.这是我不会得到回报的代码:

So, I have a simple problem which may not be possible in AppleScript. I'm attempting to return a variable from a javascript that doesn't have a return in the code. In other words, I'm trying to get the status of an element so that I can run a function conditionally. Here is the code I have that will not get a return:

tell application "Safari"
    activate
    open location "http://127.0.0.1:9999"
    delay 1
    set myVar to do JavaScript "var obj = document.getElementById(87); myVar = obj.value; return myVar;" in document 1
    return myVar
end tell

所以,基本上我试图获取 obj 的值并将其返回给 AppleScript,它应该在 0 到 255 之间(它是一个按钮).问题是,我无法控制 javascript 函数,因此无法添加 return obj.value.这可能吗?

So, basically I'm trying to get the value of obj and return it to AppleScript, which should be between 0 and 255 (it's a button). The problem is, I don't have any control over the javascript function so I can't add a return obj.value. Is this possible?

推荐答案

删除return"和var".do JavaScript"将返回最后一个全局值.例如,这应该返回 7.0:

Remove the "return" as well as the "var". "do JavaScript" will return the last global value. This, for example, should return 7.0:

tell application "Safari"
    activate
    open location "http://www.hoboes.com/Mimsy/"
    delay 1
    set myVar to do JavaScript "numbervalue=3;fred=numbervalue+4" in document 1
    return myVar
end tell

然而,这应该返回 3.0,因为这是最后一个全局值:

This, however, should return 3.0, as that’s the last global value:

tell application "Safari"
    activate
    open location "http://www.hoboes.com/Mimsy/"
    delay 1
    set myVar to do JavaScript "numbervalue=3; var fred=numbervalue+4" in document 1
    return myVar
end tell

这篇关于将 Javascript 变量返回到 AppleScript的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆