在PHP中解析jquery序列化字符串 [英] Parse a jquery serialize string in PHP
问题描述
在人们跳过我之前，我已经看到了这个帖子：我如何PHP - 反序列化jQuery序列化表单？
Before people jump all over me, I've seen this thread: How do I PHP-unserialize a jQuery-serialized form?
我的问题非常相似，但我的数据却大相径庭。我正在使用AJAX调用来做帖子，数据发布很好（jQuery是1.7）。形式&当用户点击几个链接并向下钻取到此形式时，动态加载AJAX& ajax脚本。
My question is very similar, yet my data is much different. I'm using a AJAX call to do the post, the data posts just fine (jQuery is 1.7). The form & AJAX are dynamically loaded in when a user clicks a few links and drills down to this form & ajax script.
AJAX看起来像:(顺便说一句，我知道你应该给我们.on（）但是我似乎无法让它像我一样工作。 live（））
The AJAX looks like: (BTW, I know you're supposed to us .on() but I can't seem to get that to work like I can .live() )
$('#ajaxCaptionForm').live('submit', function(e){
e.preventDefault();
$.ajax({
'type':'POST',
'data':{formData: $('#ajaxCaptionForm').serialize()},
'success':function(){
parent.$.fancybox.close();
}
});
}); // closing form submit
表格如下：
<form method="Post" action="localhost/controller" id="ajaxCaptionForm" name="ajaxCaptionForm">
<label for="Caption">Caption</label><input type="text" id="Caption" name="Caption" value="Leaf lesions.">
<label for="Keywords">Keywords</label>
<p>Please seperate keywords by a comma
<input type="text" id="Keywords" name="Keywords" value=""></p>
<input type="hidden" id="imageID" name="imageID" value="87595">
<input type="submit" value="Update Image" name="yt3" clicked="true">
</form>
序列化数据如下所示:(根据firebug）
The serialized data looks like: (according to firebug)
formData=Caption%3DFruit%2Blesions.%26Keywords%3D%26imageID%3D87592
当我回应一个回复时，我得到了这个：
When I echo out a response, I get this:
"Caption=Leaf+symptoms+of+++CCDV.&Keywords=&imageID=87655"
我的问题是：
- 关键字字段为空，即使我输入了内容
- 标题字段没有改变内容时改变帖子。
-
如何访问每个变量？标题，关键字和图像。 $ _POST也不起作用：
- The keywords field is empty, even when I put in content
- The caption field doesn't change on post when I change content.
How do i access each of the variables? Caption, Keywords and Images. $_POST does not work nor:
Yii :: app（） - > request-> getParam（'imageID'）
Yii::app()->request->getParam('imageID')
推荐答案
看来您正在制作序列化表单数据（应该已经是URL编码的键=值），作为JSON键值对中的值。这是你打算做的吗？
It appears that you're making the serialized form data (which should already be URL-encoded key=values), as the value in a JSON key-value pair. Is this what you intend to do?
来自 http://api.jquery.com/序列化/ ，请注意，通过.serialize（）发送的表单数据是标准URL编码表示法中的文本字符串。
From http://api.jquery.com/serialize/, note that the form data once sent through .serialize() "is a text string in standard URL-encoded notation."
来自 http://api.jquery.com/jQuery.ajax/ ，请注意数据设置是转换为查询字符串，如果还不是字符串。
From http://api.jquery.com/jQuery.ajax/, note that the data setting "is converted to a query string, if not already a string."
因此，您将采用标准URL编码表示法中的文本字符串，然后将其作为数据设置中键值JSON对的值。
So, you're taking a text string in "standard URL-encoded notation", and then making it the value in a key-value JSON pair in data setting.
我认为你应该是这样的（忽略live（）v。on（）问题）：
I think your could should be something like this instead (ignore the live() v. on() issue):
$('#ajaxCaptionForm').live('submit', function(e){
e.preventDefault();
$.ajax({
'type':'POST',
'data':$('#ajaxCaptionForm').serialize(),
'success':function(){
parent.$.fancybox.close();
}
});
}); // closing form submit
这也是你不能按照期望访问任何内容的原因因为它都是在'formData'键下传递的。您可以执行print_r（$ _ POST）来验证这一点，或者回显Yii :: app（） - > request-> getQueryString（）;两者都应该打印出你作为PHP数组提交的所有数据，显示键和值。
This would also be why you can't access anything as you're expecting, as it's all being passed under the 'formData' key. You can do a print_r($_POST) to verify this, or echo Yii::app()->request->getQueryString(); both should print out all the data you've submitted as a PHP array, showing you the keys and values.
作为一个建议，这是一个完美的例子，什么时候到使用Firebug控制台确切地查看正在提交的参数。
As a suggestion, this is a perfect example of when to use the Firebug console to see exactly what params are being submitted.
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