允许“/”正则表达式中的正斜杠 [英] Allow "/" forward slash in regular expression

问题描述

  var patt = / ^（？=。* [a-zA-Z0-9。！@＃& * \-\ u0080-\ u052F]）[ ！A-ZA-Z0-9\s @＃&放大器; *，\-\\\€-\\\ԯ] * $ /; 
 console.log（patt.test（\ u002f））; 
  

我知道u002f是Unicode中的正斜杠。我已经尝试将其添加到模式以及/并且还无法使其记录为真。

解决方案

很容易添加正斜杠，只是逃避它。不需要使用任何字符引用或实体。

  var patt = /^(?=.*[a-zA-Z0- ！9 @＃&安培;！* \-\\\€-\\\ԯ]）[\ / A-ZA-Z0-9\s @＃&安培; *，\-\\\€- \\\ԯ] * $ /; 
 ^ 
  

  var patt = /^(?=.* [！一个-ZA-Z0-9 @＃&安培; * \-\\\€-\\\ԯ]！）[\ / A-ZA-Z0-9\s @＃&安培; *， \-\\\€-\\\ԯ] * $ /;警报（patt.test（ /测试））;  

var patt = /^(?=.*[a-zA-Z0-9.!@#&*\-\u0080-\u052F])[a-zA-Z0-9\s.!@#&*',\-\u0080-\u052F]*$/;
console.log(patt.test("\u002f"));

I know that u002f is a forward slash in Unicode. I've tried adding that to the pattern as well as "/" and haven't been able to get it to log true yet.

解决方案

It is easy to add a forward slash, just escape it. No need using any character references or entities.

var patt = /^(?=.*[a-zA-Z0-9.!@#&*\-\u0080-\u052F])[\/a-zA-Z0-9\s.!@#&*',\-\u0080-\u052F]*$/;
                                                    ^                 

var patt = /^(?=.*[a-zA-Z0-9.!@#&*\-\u0080-\u052F])[\/a-zA-Z0-9\s.!@#&*',\-\u0080-\u052F]*$/;
alert(patt.test("/test"));

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