正则表达式 - 匹配除正斜杠以外的所有内容 [英] Regex - match everything but forward slash

问题描述

在以下字符串中:

/西雅图/餐厅

我想匹配西雅图(如果存在)(有时网址可能是/seattle/restaurant，有时可能是/restaurant).我不想要的是匹配以下正斜杠:seattle/

我尝试了以下方法，但无法正常工作:

/(.*[^/]?)restaurant(\?.*)?$

我需要第一个正斜杠，所以解决方案不是删除它，我可以这样做:

 (/?)(.*)/restaurant(\?.*)?$

谢谢

托马斯

解决方案

这样的事情怎么样?

^/([^/]+)/?(.*)$

我用 python 测试过，似乎工作正常:

<预><代码>>>>regex=re.compile(r'^/([^/]+)/?(.*)$')>>>regex.match('/seattle').groups()('西雅图'， '')>>>regex.match('/seattle/restaurant').groups()(西雅图"，餐厅")

in the following string:

/seattle/restaurant

I would like to match Seattle (if it is present) (sometimes the url might be /seattle/restaurant and sometimes it might be /restaurant). What I don't want is to match the following forward slash: seattle/

I have tried the following, but I cannot get it to work:

       /(.*[^/]?)restaurant(\?.*)?$

I need the first forward slash, so the solution is not to remove that, which I can do like this:

     (/?)(.*)/restaurant(\?.*)?$   

Thanks

Thomas

解决方案

What about something like this?

^/([^/]+)/?(.*)$

I tested it with python and seems to work fine:

>>> regex=re.compile(r'^/([^/]+)/?(.*)$')
>>> regex.match('/seattle').groups()
('seattle', '')
>>> regex.match('/seattle/restaurant').groups()
('seattle', 'restaurant')

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