使用正则表达式匹配除=以外的任何字符 [英] Using regex to match any character except =

问题描述

我正在尝试编写一个String验证来匹配任何字符（常规，数字和特殊），除了=。

I am trying to write a String validation to match any character (regular, digit and special) except =.

这是我写的 -

    String patternString = "[[^=][\\w\\s\\W]]*";
    Pattern p = Pattern.compile(patternString);
    Matcher m = p.matcher(str);

    if(m.matches())
        System.out.println("matches");
    else
        System.out.println("does not");

但是，它与输入字符串2009-09 / 09 12：23：12.5 =匹配模式。

But, it matches the input string "2009-09/09 12:23:12.5=" with the pattern.

如何从模式字符串中排除=（或任何其他字符）？

How can I exclude = (or any other character, for that matter) from the pattern string?

推荐答案

如果唯一禁止的字符是等号，那么 [^ =] * 之类的东西应该有用。

If the only prohibited character is the equals sign, something like [^=]* should work.

[^ ...] 是一个否定的字符类;它匹配单个字符，除了方括号中的列表之外的任何字符。 * 重复表达式零次或多次。

[^...] is a negated character class; it matches a single character which is any character except one from the list between the square brackets. * repeats the expression zero or more times.

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