正则表达式匹配除引号之间的单词之外的所有内容 [英] Regex match everything except words between quotes

问题描述

我想写一个正则表达式，它匹配除引号之间的单词之外的所有内容.例如:

I want to write a regex what matches everything except words between quotes. Ex.:

 Lorem ipsum "dolor" sit amet, consectetur "adipiscing" elit.
 Nunc ultrices varius odio, "ut accumsan nisi" aliquet vitae.
 "Ut faucibus augue tortor, at aliquam purus dignissim eget."

所以我想要一个匹配以下字符串的正则表达式:

So I want a regex what matches the following strings:

• Lorem ipsum
• 坐下来，consectetur
• 精英.Nunc ultrices varius odio,
• 个人简历.

我只有以下表达式匹配引号内的子字符串:

I only have the following expression that matches substrings inside quotes:

([\"'])(?:\\\1|.)*?\1

推荐答案

如果你正在使用 PCRE，你可以使用

If you are using PCRE, you may use

([\"'])(?:\\.|(?!\1)[^\\])*?\1(*SKIP)(*F)|(?:[^\\"']|\\.)+

查看其演示.

详情

• ([\"'])(?:\\.|(?!\1)[^\\])*?\1 - 一个 "..." 或 '...' 带有转义引号支持的子字符串:
  • ([\"']) - 第 1 组(用 \1 引用):一个 " 或 '
  • (?:\\.|(?!\1)[^\\])*? - 出现 0+ 次(尽可能少，因为 *? 懒惰)的:
    • \\. - 一个转义序列
    • | - 或
    • (?!\1)[^\\] - 除了 \ 和组 1 中的引号字符之外的任何字符
    • ([\"'])(?:\\.|(?!\1)[^\\])*?\1 - a "..." or '...' substring with escaped quote support:
      • ([\"']) - Group 1 (referred to with \1): a " or '
      • (?:\\.|(?!\1)[^\\])*? - 0+ occurrences (as few as possible due to *? being lazy) of:
        • \\. - an escape sequence
        • | - or
        • (?!\1)[^\\] - any char other than \ and the quote char in Group 1
        • [^\\"'] - 除了 \、' 或 " 之外的字符立>
        • \\. - 一个转义序列.
        • [^\\"'] - a char other than \, ' or "
        • \\. - an escape sequence.

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