正则表达式 - 匹配除最后一个之外的所有 [英] Regular Expression - Match all except last one
问题描述
我知道/ g标志将匹配所有出现的内容。有没有办法，用
a正则表达式来匹配所有出现*除了*最后一个？
pattern = / df / g;
var myString =" asdfasdfasdfasdf" ;;
var newString = myString.replace（pattern，''gh''）;
alert（newString）
给我：asghasghasghasgh应该如此。
我想要的是：asghasghasghasdf最后一个没有被替换的地方。
-
兰迪
comp.lang.javascript常见问题 - http://jibbering.com/faq &新闻组每周
Javascript最佳实践 - http：//www.JavascriptToolbox .com / bestpractices /
I know that the /g flag will match all occurrences. Is there a way, with
a Regular Expression, to match all occurrences *except* the last one?
pattern = /df/g;
var myString = "asdfasdfasdfasdf";
var newString = myString.replace(pattern,''gh'');
alert(newString)
Gives me: asghasghasghasgh as it should.
What I want: asghasghasghasdf Where the last one is not replaced.
--
Randy
comp.lang.javascript FAQ - http://jibbering.com/faq & newsgroup weekly
Javascript Best Practices - http://www.JavascriptToolbox.com/bestpractices/
推荐答案
> Randy Webb <您好************ @ aol.com>写道：
> "Randy Webb" <Hi************@aol.com> wrote:
新闻：Q7 ******************** @ comcast.com ....
我知道/ g标志将匹配所有出现的事件。有没有一种方法，
与正则表达式，以匹配所有出现*除了*
最后一个？
pattern = / df / g;
var myString =" asdfasdfasdfasdf" ;;
var newString = myString.replace（pattern，''gh''）;
alert（newString）
给我：asghasghasghasgh应该如此。
我想要的是：asghasghasghasdf最后一个没有被替换的地方。
news:Q7********************@comcast.com....
I know that the /g flag will match all occurrences. Is there a way,
with a Regular Expression, to match all occurrences *except* the
last one?
pattern = /df/g;
var myString = "asdfasdfasdfasdf";
var newString = myString.replace(pattern,''gh'');
alert(newString)
Gives me: asghasghasghasgh as it should.
What I want: asghasghasghasdf Where the last one is not replaced.
字符串是否总是以模式结束？
-
BootNic 2006年3月19日星期日上午1:19
这并不是说有些人有意志力，有些人不会。这是
有些人准备改变而其他人则没有。
* James Gordon *
Does the string always end with the pattern?
--
BootNic Sunday, March 19, 2006 1:19 AM
It''s not that some people have willpower and some don''t. It''s that
some people are ready to change and others are not.
*James Gordon*
BootNic在3/19/2006 1:20 AM上发表以下内容：
BootNic said the following on 3/19/2006 1:20 AM:
" Randy Webb" <您好************ @ aol.com>写道：
新闻：Q7 ******************** @ comcast.com ....
我知道/ g标志将匹配所有出现。有没有一种方法，
与正则表达式，以匹配所有出现*除了*
最后一个？
模式= / df / g;
var myString =" asdfasdfasdfasdf";
var newString = myString.replace（pattern，''gh''）;
alert（newString）
给我：asghasghasghasgh应该如此。
我想要的是：asghasghasghasdf最后一个没有被替换的地方。
"Randy Webb" <Hi************@aol.com> wrote:
news:Q7********************@comcast.com....
I know that the /g flag will match all occurrences. Is there a way,
with a Regular Expression, to match all occurrences *except* the
last one?
pattern = /df/g;
var myString = "asdfasdfasdfasdf";
var newString = myString.replace(pattern,''gh'');
alert(newString)
Gives me: asghasghasghasgh as it should.
What I want: asghasghasghasdf Where the last one is not replaced.
字符串总是以模式结束吗？
Does the string always end with the pattern?
是的。而且我想我知道你要去哪里但是我会等着看看:)
我实际匹配的模式是\\\\ n，字符串是.value
的textarea。它将替换为; \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\ $ b为他们创建document.write语句。我最后得到的结果
是一个额外的document.write（我不想要的。
我总是可以直接替换document.write的最后一次出现（但是我/ b $ b希望有一个更简单的解决方案。
-
Randy
comp.lang.javascript常见问题 - http： //jibbering.com/faq & newsgroup每周
Javascript最佳实践 - http://www.JavascriptToolbox.com/bestpractices/
Yes. And I think I know where you are headed but I will wait and see :)
The pattern I am actually matching is \r\n and the string is the .value
of a textarea. It is replacing it with ";\r\ndocument.write("
Where the " is part of the replacement. All it does is take code and
create document.write statements for them. What I end up with at the end
is an extra document.write(" that I don''t want.
I could always just replace the last occurence of document.write(" but I
was hoping there was a simpler solution.
--
Randy
comp.lang.javascript FAQ - http://jibbering.com/faq & newsgroup weekly
Javascript Best Practices - http://www.JavascriptToolbox.com/bestpractices/
>" Randy Webb"< Hi *** *********@aol.com>写道：
> "Randy Webb" <Hi************@aol.com> wrote:
新闻：qZ ******************** @ comcast。 COM .... <无线电通信/>
BootNic在3/19/2006 1:20 AM上发表以下内容：
news:qZ********************@comcast.com....
BootNic said the following on 3/19/2006 1:20 AM:
" Randy Webb" <您好************ @ aol.com>写道：
新闻：Q7 ******************** @ comcast.com ....
我知道/ g标志将匹配所有出现。是否有一个
方式，使用正则表达式来匹配所有出现*除了*
最后一个？
pattern = / df / g;
var myString =" asdfasdfasdfasdf";
var newString = myString.replace（pattern，''gh''）;
alert（newString）
给我：asghasghasghasgh应该如此。
我想要的是：asghasghasghasdf最后一个没有被替换的地方。
"Randy Webb" <Hi************@aol.com> wrote:
news:Q7********************@comcast.com....
I know that the /g flag will match all occurrences. Is there a
way, with a Regular Expression, to match all occurrences *except*
the last one?
pattern = /df/g;
var myString = "asdfasdfasdfasdf";
var newString = myString.replace(pattern,''gh'');
alert(newString)
Gives me: asghasghasghasgh as it should.
What I want: asghasghasghasdf Where the last one is not replaced.
字符串总是以模式结束吗？
Does the string always end with the pattern?
是的。而且我想我知道你要去哪里但是我会等着看
我实际匹配的模式是\\\\ n，字符串是
。文本区域的价值。它将替换为; \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\我最终得到的是
结尾是一个额外的document.write（我不想要的。
我总是可以替换文档的最后一次出现。写（
但我希望有一个更简单的解决方案。
Yes. And I think I know where you are headed but I will wait and
see :)
The pattern I am actually matching is \r\n and the string is the
.value of a textarea. It is replacing it with ";\r\ndocument.write("
Where the " is part of the replacement. All it does is take code and
create document.write statements for them. What I end up with at
the end is an extra document.write(" that I don''t want.
I could always just replace the last occurence of document.write("
but I was hoping there was a simpler solution.
现在，我不认为我理解这种情况。听起来好像
你需要在
替换之前去除刺痛两端的空白区域。
但是我不要以为这就是问题。
我要建议两件事之一。
pattern = / df（？ =。）/ g;
var myString =" asdfasdfasdfasdf" ;;
var newString = myString.replace（pattern，''gh''）;
alert（newString）;
或
var myString =" asdfasdfasdfasdf";
while（myString.match（/ df / g）。length！= 1）{
myString = myString.replace（/ df / ，''gh''）
}
alert（myString）;
-
BootNic 2006年3月19日星期日2:21
首先获取您的信息，然后您可以歪曲它们
please。
* Mark Twain *
Well now, I don''t think I am comprehending the situation. It sounds like
you need to strip the the white space on each end of the sting before the
replace.
But I don''t think that is the issue.
I was going to suggest one of two things.
pattern = /df(?=.)/g;
var myString = "asdfasdfasdfasdf";
var newString = myString.replace(pattern,''gh'');
alert(newString);
Or
var myString = "asdfasdfasdfasdf";
while(myString.match(/df/g).length!=1){
myString=myString.replace(/df/,''gh'')
}
alert(myString);
--
BootNic Sunday, March 19, 2006 2:21 AM
Get your facts first, and then you can distort them as much as you
please.
*Mark Twain *
这篇关于正则表达式 - 匹配除最后一个之外的所有的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
