在正则表达式中添加DOT（。） [英] Adding a DOT (.) to Regular Expression

问题描述

我想在下面的函数中为允许的字符添加一个（。）：

I'm looking to add a (.) to the allowed characters in my function below:

$(id).bind('keypress', function(event) {
    var regex = new RegExp("[()a-zA-Z0-9 ?,/-]");
    var key = String.fromCharCode(!event.charCode ? event.which : event.charCode);
    if (!regex.test(key)) {
        event.preventDefault();
        return false;
    }
});

但是，每次我添加它都会出现错误：

However, every time I add it it comes up with the error:

未捕获的SyntaxError：无效的正则表达式：/ [（）a-zA-Z0-9
？，/ - 。] /：无序的范围字符类

Uncaught SyntaxError: Invalid regular expression: /[()a-zA-Z0-9 ?,/-.]/: Range out of order in character class

我尝试添加（。）&也尝试用（ \。）添加它但仍然是同样的错误。

I've tried adding just (.) & also tried adding it with (\.) but still the same error.

请你协助到哪里我需要添加这个（。）？

Please can you assist to where I need to add this (.) ?

推荐答案

注意 - 应该在字符类的开头或结尾处，或者必须用反斜杠 \ 进行转义，因为它表示范围，如 az

Note that - should either be at the beginning or at the end of character class or has to be escaped by a backslash \, since it indicates range as in a-z

/[()a-zA-Z0-9 ?,/.-]/

此外，如果需要动态正则表达式，只需使用上面的正则表达式文字，如果没有，你必须删除分隔符 / / 并使用实际的正则表达式 [（）a-zA-Z0-9？，/ .-] 作为字符串，可在 RegExp 构造函数。

Also, if dynamic regex is required, just use the regex literal as in above, if not you'd have to remove the delimiters / / and use the actual regex [()a-zA-Z0-9 ?,/.-] as a String which can be used in RegExp constructor.

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