从对象中抓取字段并将其返回到数组中 [英] Grabbing fields from object and returning it in an array

问题描述

我有两个链接对象

{scope: "T4251", data: Array(500)}
{scope: "T7910", data: Array(500)}
{scope: "T213910", data: Array(500)}

，数据对象包含500个这些字段（范围链接到下面）

and the data object consists of 500 of these fields (scope is linked to below)

{@id: "eddnsf", dateTime: "2018-12-12T07:30:00Z", value: -0.045}
{@id: "sfdkjk", dateTime: "2018-12-12T04:30:00Z", value: -0.345}
{@id: "dfjewf", dateTime: "2018-11-12T02:00:00Z", value: -0.445}
{@id: "dfjewf", dateTime: "2018-10-12T04:40:00Z", value: -0.045}
{@id: "dfjewf", dateTime: "2018-10-12T06:00:00Z", value: -0.145}
{@id: "dfjewf", dateTime: "2018-10-12T02:00:00Z", value: -0.045}

如何通过首先获取一个唯一的范围对象来迭代这个多对象，然后在每个日期（必须是唯一的）对象中抓取dateTime，包含在范围的数组对象？

How do I iterate this multi-object by first getting a unique "scope" object then grabbing the dateTime only once per date (must be unique) objects from the data array contained in the scope's array object?

我想要的抓住要放入单个数组的唯一dateTime

I want the unique dateTime grabbed to be put into a single array

数组应该导致：

[unique dateTime, unique dateTime, unique dateTime] 

推荐答案

你可以用两个功能来做。
首先收集dateTimes

You could do it with two functions. First collects the dateTimes

const extractField= (data, field) => data.map( obj => obj[field])

第二次过滤双打

const filterDoubles = array => array.reduce( (result, item) => result.indexOf(item) > -1 ? result : result.concat(item),[])

然后：

filterDoubles(extractField(yourObject, 'dateTime'));

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