比较具有不同数量属性的两个数组,并使用javascript在条件下将第三个数组与比较值映射 [英] compare two arrays having different number of properties and mapping a third array with compared values on condition using javascript
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问题描述
我有2个数组
var array1 = ["1", "2", "3", "4", "5", "6"]
和
var array2 = [
{ offId: "4", offname: "four" },
{ offId: "9", offname: "nine" },
{ offId: "15", offname: "fifteen" },
{ offid: "3", offname: "three" },
{ offId: "1", offname: "one" },
{ offId: "0", offname: "zero" },
{ offId: "8", offname: "eight" },
{ offId: "10", offname: "ten" },
]
我需要比较两个值为offId和结果数组的数组应为
i need to compare two arrays with the values of offId and the resulted array should be
var array3 = [
{ offId: "1", offname: "one" },
{ offId: "2", offname: "" },
{ offId: "3", offname: "three" },
{ offId: "4", offname: "four" },
{ offId: "5", offname: "" },
{ offId: "6", offname: "" },
]
我怎样才能实现这个目标(阵列长度可能相同或不同)租金)
How could i achieve this(length of the array may be same or different)
推荐答案
你可以拿一个 Map
并使用存储的对象或新对象。
You could take a Map
and use either the stored object or a new object.
var array1 = ["1", "2", "3", "4", "5", "6"],
array2 = [{ offId: "4", offname: "four" }, { offId: "9", offname: "nine" }, { offId: "15", offname: "fifteen" }, { offId: "3", offname: "three" }, { offId: "1", offname: "one" }, { offId: "0", offname: "zero" }, { offId: "8", offname: "eight" }, { offId: "10", offname: "ten" }],
map = array2.reduce((m, o) => m.set(o.offId, o), new Map),
result = array1.map(offId => map.get(offId) || { offId, offname: '' });
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
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